Well the case with the droughts is that the water supply comes from different places such as other smaller streams and also from underground rivers .Rivers cut into saturated ground is also another reason.
Answer:
a: after 1 seconds it will have fallen 0.2452
after 2 seconds it will have fallen 0.981
after 3 seconds it will have fallen 2.2072
after 4 seconds it will have fallen 3.924
Explanation:
the formula for acceleration due to gravity is (ignoring friction I think)
g = G*M/R^2
earths gravitational constant is about 9.807
g = 9.807*M/R^2
The average weight of a brick is 5 pounds and I'm going to say it's 10 feet off the ground.
g = 9.807*5/10^2. g = 0.4905 so every second the brick will go 0.4905 fps faster. (fps means feet per second.)
after 1 seconds it will have fallen 0.2452
after 2 seconds it will have fallen 0.981
after 3 seconds it will have fallen 2.2072
after 4 seconds it will have fallen 3.924
G: V=120v and I=.75amps
U: R=?
S: To fins the resistance of the lightbulb you’d have V divided into I so,
S: 120/.75 = Therefore the resistance is 160ohm
Sorry I'm late. Also sorry you couldn't handle any of this on your own.
There's not that much to it. If you ignore friction, then the total energy
is constant.
-- At the top, it's all potential energy, and kinetic energy is zero.
-- At the bottom, potential energy is zero and it's all kinetic energy.
-- Halfway down, it's half potential energy and half kinetic energy.
The real truth is that there's always some friction, friction robs kinetic
energy whenever he's moving, so eventually he stops going up and
down. Then he has to put some muscle energy into it to go some more.
Answer:
The correct option is;
(A) 1 m/s
Explanation:
Given that Ramu and Somu are running towards North with 3 m/s and 4 m/s respectively.
Their friend Srinu is running towards South with a speed of 2 m/s
The magnitude of the relative velocity of Ramu with respect to Ramu is found as follows;
Velocity of Ramu = 3 m/s North ↑
Velocity of Srinu = 2 m/s South↓ = -2 m/s North ↑
Relative velocity of Ramu to Srinu = Velocity of Ramu North + Velocity of Srinu North
Relative velocity of Ramu to Srinu = 3 m/s + (-2) m/s = (3 - 2) m/s = 1 m/s
Relative velocity of Ramu to Srinu = 1 m/s.
