Question

A 63 kg astronaut is drifting in space at a velocity of 7.0 m/s to the right with respect to the spacecraft. The astronaut uses the jetpack to move to the left and back to the spacecraft. The jetpack fires for 14.0 seconds and the astronaut makes it back to the ship. What was the force exerted by the jetpack? AND for extra credit, how far away from the ship where they?
J = Δp = m Δv = F Δt
Impulse = change in momentum = mass x change in velocity = force x time interval

Answer 1

Answer:

force exerted by Jet pack is 63 N on the astronaut

Explanation:

As per Newton's II law we know that

Rate of change in momentum of the system is net force on it

so we have

$F = \frac{\Delta P}{\Delta t}$

so we have

$F = \frac{m(v_f - v_i)}{\Delta t}$

so we have

Since he used jet pack to return back towards the spaceship

so here we will have

$v_f = 7 m/s$

$v_i = -7 m/s$

$F = \frac{63(7 + 7)}{14}$

$F = 63 N$

force exerted by Jet pack is 63 N on the astronaut