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kotegsom [21]
3 years ago
11

Nadia buys boxes of crackers that each has the same cost c. She represents the cost of 6 boxes of cheese crackers, 5 boxes of po

ppys seed crackers, and 5 boxes of plain crackers using the expression 6c + 5c + 5c. What equivalent expression can represent the cost.
Mathematics
2 answers:
snow_lady [41]3 years ago
6 0
I believe the answer is b because u need to combine like terms and 6c+2c+5c is 13c.
skelet666 [1.2K]3 years ago
4 0

<u>To</u><u> Find</u><u> </u><u>:</u><u>-</u>

  • The equivalent expression that represents the cost .

<u>Solution</u><u> </u><u>:</u><u>-</u>

Here according to the question ,

\longrightarrow Cost \ of \ each \ crackers \ = \ c

And , she purchases ,

\longrightarrow \textit{ boxes of cheese crackers = 6 } \\\\\longrightarrow\textit{ boxes of poppy's seed crackers = 5 }\\\\\longrightarrow \textit{ boxes of plain crackers = 5 }

And she represents cost by ,

\longrightarrow Cost = 6c + 5c + 5c

To find equivalent , take out c as common ,

\longrightarrow Cost = c (6+5+5)

Add the constant terms inside the brackets ,

\longrightarrow Cost = c \times 16

Multiply ,

\longrightarrow \underline{\underline{Cost = 16c }}

<u>Hence</u><u> the</u><u> </u><u>equivalent</u><u> </u><u>expression</u><u> </u><u>is </u><u>1</u><u>6</u><u>c</u><u> </u><u>.</u>

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Answer:

Option (b) is correct.

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Given: (2^\frac{1}{4} )^4

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We have,

(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}

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We have,

(2^\frac{1}{4} )^4=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}

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