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2 years ago

Hey guys happy Tuesday ! I need some home work help ASAP work and answer pls love y’all ❤️

Mathematics

1 answer:

Strike441 [17]2 years ago

8 0

1. Multiply 5 by 2 since the piece is twice as long. That is 10.
Multiply 4 by 3 since the piece is 3 times as long. That is 12.
Her piece is 10 x 12.
2 sides of 10 & 2 sides of 12.
Multiply 10 & 12 by 2 to get 20 and 24. Add them together to get 44 inches, which is the perimeter.

2. Multiply 4 x 2 since length is twice width. That is 8.
Multiply 8 x 4 to get the area of the red paper. That is 32.
Multiply 3 x 7 to get the area of the blue paper. That is 21.
Subtract 21 from 32 to get the amount of red paper that wasn't covered up.
11 square cm were not covered up.

Hope this helps!

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The present shown below is a cube.

anastassius [24]

Answer:

SA = 2400 cm²

Step-by-step explanation:

SA of a cube = S² x 6 (the number of its faces)

SA = 20² x 6

SA = 400 x 6

SA = 2400 cm²

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2 years ago

Explain why 7 times x/7=x. How does your answer help you solve a division equation such as x/7=2?

tatiyna

Dear Ajtocute, let's have x=9 Multiply 7 by 9 to get 63. Then, you divide 63 by 7 to get back to 9. You just cancel out the multiplication with division.

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2 years ago

Find the values of x and y.

DENIUS [597]

X = 20 degrees
Y = 30
This is acute triangle so all the sides and angles are the same. Subtract 16 from 46 and you receive 30 for y. For the corresponding angle, subtract 80 from 180. Then add 60 to that and subtract that from 180 for x.

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2 years ago

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago

Jamie ordered 24 combo meals for $5 each for a party. The service charge for home delivery for the whole purchase was $6.

My name is Ann [436]

24 * 5 = 120
120 + 6 = 126 - total cost - meals and service

6/126 *100% = 4,76%

service charge was 4,76% of total costs.

3 0

3 years ago