Answer:
(b) 
Step-by-step explanation:
When two p and q events are independent then, by definition:
P (p and q) = P (p) * P (q)
Then, if q and r are independent events then:
P(q and r) = P(q)*P(r) = 1/4*1/5
P(q and r) = 1/20
P(q and r) = 0.05
In the question that is shown in the attached image, we have two separate urns. The amount of white balls that we take in the first urn does not affect the amount of white balls we could get in the second urn. This means that both events are independent.
In the first ballot box there are 9 balls, 3 white and 6 yellow.
Then the probability of obtaining a white ball from the first ballot box is:
In the second ballot box there are 10 balls, 7 white and 3 yellow.
Then the probability of obtaining a white ball from the second ballot box is:
We want to know the probability of obtaining a white ball in both urns. This is: P(
and 
)
As the events are independent:
P( and ) = P () * P ()
P( and ) = 
P( and ) =
Finally the correct option is (b)
Answer:
0.00
Step-by-step explanation:
1880mL is not even 1 pint
Answer:
m<1= 120
Step-by-step explanation:
1. we know supplementary angles equals 180. the angle 130 is part of a supplementary angle so we can subtract it by 180 to see that missing angle.
2. we also know that all triangles three angles add up to 180. So if we add the number we know 70+50 (50 is from subtracting 130 from 180), Once we find that answer, we subtract it from 180 to find angle 2 which is 60 degrees
3. Last step, angle 2 is part os a supplementary angle in which the two angles add up to 180. So, subtracting 60 from 180 will get you the degree of the angel one which his 120 degrees.
Answer:
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Step-by-step explanation:
Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.
Let five years ago be group I X and as of now be group II Y
(Two tailed test at 5% level of significance)
Group I Group II combined p
n 270 300 570
favor 120 140 260
p 0.4444 0.4667 0.4561
Std error for differene = 
p difference = -0.0223
Z statistic = p diff/std error = -1.066
p value =0.2864
Since p value >0.05, we accept null hypothesis.
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Answer:
w = -10
Step-by-step explanation:
w + 4 = (-6)
Subtract 4 from each side
w+4-4 = -6-4
w = -10
