Question

First answer = brainliest

Answer 1

Answer:

33.51032

Step-by-step explanation:

V=4/3πr^3=4/3·π·2^3≈33.51032

Answer 2

Answer:

V ≈ ${\boxed{\sf{\green{32}}}}$ cm³

Step-by-step explanation:

DIAGRAM :

$\setlength{\unitlength}{1.2cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\qbezier(-2.3,0)(0,-1)(2.3,0)\qbezier(-2.3,0)(0,1)(2.3,0)\thinlines\qbezier (0,0)(0,0)(0.2,0.3)\qbezier (0.3,0.4)(0.3,0.4)(0.5,0.7)\qbezier (0.6,0.8)(0.6,0.8)(0.8,1.1)\qbezier (0.9,1.2)(0.9,1.2)(1.1,1.5)\qbezier (1.2,1.6)(1.2,1.6)(1.38,1.9)\put(0.2,1){\bf{2\ cm}}\end{picture}$

$\begin{gathered}\end{gathered}$

SOLUTION :

Here's the required formula to find the volume of sphere :

$\longrightarrow{\pmb{\sf{V = \dfrac{4}{3} \pi {r}^{3}}}}$

• V = Volume
• π = 3
• r = radius

Substituting all the given values in the formula to find the volume of sphere :

$\longrightarrow{\sf{V_{(Sphere)} = \dfrac{4}{3} \pi {r}^{3}}}$

$\longrightarrow{\sf{V_{(Sphere)} = \dfrac{4}{3} \times 3 \times {(2)}^{3}}}$

$\longrightarrow{\sf{V_{(Sphere)} = \dfrac{4}{3} \times 3 \times {(2 \times 2 \times 2)}}}$

$\longrightarrow{\sf{V_{(Sphere)} = \dfrac{4}{3} \times 3 \times {(4 \times 2)}}}$

$\longrightarrow{\sf{V_{(Sphere)} = \dfrac{4}{3} \times 3 \times (8)}}$

$\longrightarrow{\sf{V_{(Sphere)} = \dfrac{4}{\cancel{3}}\times \cancel{3} \times 8}}$

$\longrightarrow{\sf{V_{(Sphere)} = 4 \times 8}}$

$\longrightarrow{\sf{V_{(Sphere)} = 32}}$

$\star{\boxed{\sf{\red{V_{(Sphere)} \approx 32 \: {cm}^{3}}}}}$

Hence, the volume of sphere is 32 cm³.

$\begin{gathered}\end{gathered}$

LEARN MORE :

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$

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