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LiRa [457]
2 years ago
7

SOMEONE HELP ASAP PLEASE

Mathematics
1 answer:
ziro4ka [17]2 years ago
7 0
Step 1:Distribute -2 into 5 and 8
Step 2:Subtract 6x from both sides
Step3: Add 16 to both sides
Step 4: Divide -16 into 30
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What is the coefficient of x^2 in the expansion of (x+2)^3
goldenfox [79]
(x+2)^3=x^3+2^3+3*x^2*2+3x*2^2=x^3+8+6x^2+12x

The coeficient of the x^2 is 6.
3 0
3 years ago
What is the difference of 3.14 and the sum of 5.99 and 0.65?
charle [14.2K]

Answer:

3.5

Step-by-step explanation:

5.99+0.65=6.64

6.64-3.14=3.5

3 0
3 years ago
What is -7 (5-4x)=21
Ray Of Light [21]
-35 + 28x = 21

28x = 56

x = 2
8 0
3 years ago
WILL GIVE BRAINIEST 2.find the values of x and y a. x=15 y=12 b.x=14 y=11 c.x=14 y=12 d.x=15 y=11
liubo4ka [24]

3x - 7 = 2x + 7

3x - 2x = 7 + 7

x = 14


2x + 7 + 12y + 1 = 180

2(14) + 7 +  12y + 1 = 180

12y + 36 = 180

12y = 144

y = 12

Answer

x = 14 and y = 12

4 0
3 years ago
At what rates did she invest?<br> $1400 invested at ____%<br> $900 invested at ____%
Mars2501 [29]

9514 1404 393

Answer:

  • $1400 at 8%
  • $900 at 10%

Step-by-step explanation:

The 1-year interest is simply the invested amount times the interest rate.

Let r represent the lower interest rate. Then r+0.02 is the higher rate, and the total interest earned is ...

  1400r + 900(r +.02) = 202

  2300r +18 = 202 . . . . . . . . . .simplify

  2300r = 184 . . . . . . . . . .subtract 18

  r = 184/2300 = 0.08 = 8% . . . . . . divide by the coefficient of r

$1400 was invested at 8%.

$900 was invested at 10%.

5 0
3 years ago
Read 2 more answers
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