The equation that models the movement of the object is:
Where,
t: time
a: acceleration due to gravity
v0: initial speed
h0: initial height
Suppose that the object falls with zero initial velocity and from a height of 38 feet.
The equation that models the problem is:
Answer:
If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds
Answer:
Option A) Inside the circle
Step-by-step explanation:
step 1
Find the radius of the circle
we know that
The radius is equal to the distance from the center to any point on the circle
the formula to calculate the distance between two points is equal to
we have
A(-5,-8),M(-1,-3)
substitute the values
step 2
Find the distance from the center to point V
we know that
If the distance from the center to point V is equal to the radius, then the point V lie on the circle
If the distance from the center to point V is less than the radius, then the point V lie inside the circle
If the distance from the center to point V is greater than the radius, then the point V lie outside the circle
we have
A(-5,-8),V(-11,-6)
substitute in the formula
so
The distance from the center to point V is less than the radius
therefore
The point V lie inside the circle
Hope that helped :)
Answer:
(1, 7)
Step-by-step explanation:
Substitute x = 1 into the equation for the corresponding value of y
y = 2x + 5 = (2 × 1) + 5 = 2 + 5 = 7
Solution is (1, 7)
F(x)=0
f(x)=y
so where y=0, the x value is the x in f(x)
basically, where the line crosses or touches the x axis, those ar the x values that make the function true
Find the volume of the silo.
The formula is: Volume = PI x r^2 x h
Replace volume with the volume of grain and solve for h:
38000 = 3.14 x 24^2 x h
38000 = 3.14 x 576 x h
38000 = 1808.64 x h
Divide both sides by 1808.64
h = 38000 / 1808.64
h = 21.01
The grain would be 21.01 feet ( round to 21 feet.)
