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AysviL [449]
3 years ago
10

When naming binary covalent compounds, the element listed first will be the one that is.

Chemistry
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer:

Rule 1. The element with the lower group number is written first in the name; the element with the higher group number is written second in the name. Exception: when the compound contains oxygen and a halogen, the name of the halogen is the first word in the name.

Explanation:

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3 years ago
13.0 g NaHSO4 is dissolved in water to make a 2.00 L solution what is the molarité
Sati [7]

Answer:

0.054 M

Explanation:

1 mol NaHSO4 -> 120 g

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x= 0.108 mol NaHSO4

M= mol solute/ L solution

M= 0.108 mol NaHSO4/ 2.00L

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8 0
3 years ago
___Al+NaOH=>__Na3AlO3+H2
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Explanation:

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<em><u>...</u></em>

8 0
3 years ago
How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?
meriva

Answer:

\large \boxed{\text{77.4 mL}}

Explanation:

                Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

    V/mL:     249

c/mol·L⁻¹:  0.0443     0.285

1. Calculate the moles of Ba(OH)₂

\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1  mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}

3. Calculate the volume of HCl

V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}

8 0
3 years ago
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A farmer can be more successful in understanding which plant produces and how to grow plants with a higher degree of photosynthesis with less material and time exhaustion, by recognizing what the limiting factor is.

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