I think it is the bottom left :)
Answer:
the heat rate required to cool down the gas from 535°C until 215°C is -2.5 kW.
Explanation:
assuming ideal gas behaviour:
PV=nRT
therefore
P= 109 Kpa= 1.07575 atm
V= 67 m3/hr = 18.6111 L/s
T= 215 °C = 488 K
R = 0.082 atm L /mol K
n = PV/RT = 109 Kpa = 1.07575 atm * 18.611 L/s /(0.082 atm L/mol K * 488 K)
n= 0.5 mol/s
since the changes in kinetic and potencial energy are negligible, the heat required is equal to the enthalpy change of the gas:
Q= n* Δh = 0.5 mol/s * (- 5 kJ/mol) =2.5 kW
Answer:
The answer to your question is the letter d. S
Explanation:
Data
Change of +4 in the oxidation number
Chemical reaction
K₂Cr₂O₇ + H₂O + S ⇒ KOH + Cr₂O₃ + SO₂
Process
1.- Calculate the oxidation numbers following the rules.
Some rules
H = +1 O = -2 Alkali metals = + 1 Alkali earth metals = +2
K₂⁺¹Cr₂⁺⁶O₇⁻² + H₂⁺¹O⁻² + S⁰ ⇒ K⁺¹O⁻²H⁺¹ + Cr₂⁺³O₃⁻² + S⁺⁴O₂⁻²
Elements that changed their oxidation numbers
Cr₂⁺⁶ ---------------- Cr₂⁺³
S⁰ --------------- S⁺⁴
Answer:
Where are these Chambers located ], there is hundreds of them in the world
Answer:
NH2- has two pairs of bonding and two pairs of non-bonding electrons participated in the formation of a molecule. The central nitrogen atom has two pairs of non-bonding electrons cause repulsion on both bonding pairs which pushes the bonds closer to each other. So, NH2- has a bent (angular) molecular geometry.
Explanation:
