The balanced equation for the formation of ammonia is as follows;
N₂ + 3H₂ ---> 2NH₃
stoichiometry is the molar ratio of components in a reaction.
Stoichiometry could be determined using the coefficients of the compounds in balanced reactions.
coefficient of N₂ - 1
coefficient of H₂ - 3
molar ratio of N₂ to H₂ is 1:3
<span>(2) 1:3</span>
Since there are 22.4 L/mol at STP, you would convert 1000mL to 1 L then divide that by 22.4, meaning your answer would be 0.0446 rounded to 0.04
Answer:
a) ![\Delta S](https://tex.z-dn.net/?f=%5CDelta%20S%3C0)
b) entropy of the sistem equal to a), entropy of the universe grater than a).
Explanation:
a) The change of entropy for a reversible process:
![\delta S=\frac{\delta Q}{T}](https://tex.z-dn.net/?f=%5Cdelta%20S%3D%5Cfrac%7B%5Cdelta%20Q%7D%7BT%7D)
![\Delta S=\frac{Q}{T}](https://tex.z-dn.net/?f=%5CDelta%20S%3D%5Cfrac%7BQ%7D%7BT%7D)
The energy balance:
![\delta U=[tex]\delta Q- \delta W](https://tex.z-dn.net/?f=%5Cdelta%20U%3D%5Btex%5D%5Cdelta%20Q-%20%5Cdelta%20W)
If the process is isothermical the U doesn't change:
![0=[tex]\delta Q- \delta W](https://tex.z-dn.net/?f=0%3D%5Btex%5D%5Cdelta%20Q-%20%5Cdelta%20W)
![\delta Q= \delta W](https://tex.z-dn.net/?f=%5Cdelta%20Q%3D%20%5Cdelta%20W)
![Q= W](https://tex.z-dn.net/?f=Q%3D%20W)
The work:
![W=\int_{V1}^{V2}P*dV](https://tex.z-dn.net/?f=W%3D%5Cint_%7BV1%7D%5E%7BV2%7DP%2AdV)
If it is an ideal gas:
![P=\frac{n*R*T}{V}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7Bn%2AR%2AT%7D%7BV%7D)
![W=\int_{V1}^{V2}\frac{n*R*T}{V}*dV](https://tex.z-dn.net/?f=W%3D%5Cint_%7BV1%7D%5E%7BV2%7D%5Cfrac%7Bn%2AR%2AT%7D%7BV%7D%2AdV)
Solving:
![W=n*R*T*ln(V2/V1)](https://tex.z-dn.net/?f=W%3Dn%2AR%2AT%2Aln%28V2%2FV1%29)
Replacing:
![\Delta S=\frac{n*R*T*ln(V2/V1)}{T}](https://tex.z-dn.net/?f=%5CDelta%20S%3D%5Cfrac%7Bn%2AR%2AT%2Aln%28V2%2FV1%29%7D%7BT%7D)
![\Delta S=n*R*ln(V2/V1)}](https://tex.z-dn.net/?f=%5CDelta%20S%3Dn%2AR%2Aln%28V2%2FV1%29%7D)
Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:
![\Delta S](https://tex.z-dn.net/?f=%5CDelta%20S%3C0)
b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.