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diamong [38]
1 year ago
8

6. Write the equation of the line in slope-intercept form that has the following points: (1, -3) (0, -5)

Mathematics
1 answer:
Troyanec [42]1 year ago
7 0

Answer:

y = 2x −5

Step-by-step explanation:

The slope is 2 and the Y intercept is -5 so the equation is:

y = 2x -5

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At a pet shop 5 herbals out of 15 have black hair and 3 mice out of 9 have black hair. Are the ratios the Same?
dmitriy555 [2]

Answer: Yes.

Step-by-step explanation:

First ratio

5 : 15

Simplify (divide both sides by 5)

1 : 3

Second Ratio

3 : 9

Simplify (divide both sides by 3)

1 : 3

8 0
3 years ago
El diámetro de la ranura de la parte superior de un recipiente metálico es de 1.94 in ¿Cuál
zzz [600]
49.276 mm, (25.4 mm•x in) es la ecuación para convertir las pulgadas a milímetros
5 0
3 years ago
An icecube is made of 5 fluid ounces of water. About how many millilters of water does it take to make to the icecube. Round my
Dafna11 [192]

It takes 147.87 milliliter to make ice cube

<em><u>Solution:</u></em>

Given that ice cube is made of 5 fluid ounces of water

To find: milliliters of water to make to the ice cube

So we have to convert 5 ounce to milliliter

<em><u>Use the following conversion factor</u></em>

1 ounce = 29.5735 milliliter

Therefore,

5 ounce = 5 x 29.5735 milliliter

5 ounce = 147.8675 milliliter

On rounding to nearest hundred ( 2 decimal places ) , we get

5 ounce = 147.87 milliliter

Thus it takes 147.87 milliliter to make ice cube

5 0
2 years ago
Please help as soon as possible
Gemiola [76]
-3.7, 12/20, and 330%
4 0
1 year ago
Read 2 more answers
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
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