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AleksAgata [21]
3 years ago
15

Kyle is hanging wallpaper in his bedroom. A roll of wallpaper is 5 feet long. Kyle cuts off a piece of wallpaper 2 5/6 feet long

. How much wallpaper is left on the roll (*Hint-be sure to regroup)? please help i'm stuck :((((((
Mathematics
2 answers:
Dmitriy789 [7]3 years ago
8 0
2 feet and 2 inches are left
Korvikt [17]3 years ago
6 0

Answer: (5 feet) - ((2 5/6) feet) =

2.16666667 feet (2 feet 2 inches)

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Solve the equation by finding the square roots<br>w^2-36=-64​
sammy [17]

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : w^2-36-(-64)=0 Step by step solution : Step 1 : Polynomial Roots Calculator : 1.1 Find roots (zeroes) of : F(w) = w 2 +28 so the answer could be 2.176 or 30.

8 0
4 years ago
What are the coordinates of the midpoint for segment AB if A is (14 , -2) and B is (7 , -8)
Alenkasestr [34]

Answer:

Step-by-step explanation:

(14 + 7)/2 = 21/2= 10.5

(-2 + (-8))/2= -10/2= -5

Midpoint(10.5, -5)

5 0
3 years ago
PLEASE HELP question 30
weeeeeb [17]

Answer:

B

Step-by-step explanation:

d+c=180 because 360 degrees are in the parrallegram so divide that by 2 so 114+c=180 so

c=66

3 0
3 years ago
3(x+1)=5(x−2)+7<br> solve for x
bearhunter [10]
X=3

3(3+1)=12

5(3-2)+7=12
8 0
2 years ago
Really need help guys!<br> Love you if you can solve them wiz steps!!!!
Marta_Voda [28]

Answer:

Step-by-step explanation:

x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3}  \\\sqrt{D}=4\sqrt{3}  \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}

c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16

d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6

5 0
2 years ago
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