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ss7ja [257]
3 years ago
5

What is the surface area of a cube with a edge of 5

Mathematics
1 answer:
sergejj [24]3 years ago
7 0

Answer:

Step-by-step explanation:

A cube is made up of 6 squares

One square has 4 edges of equal length

The area of one face is Area = s^2

Therefore the surface area is 6 * s^2

The area of this cube is 6 * 5 * 5 = 150 units.

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Determine the value of the variable. 5 + 17 = J - 14
Nataly_w [17]
You would add 5 and 17 and that would equal 22
Now it would be 22=J-14
Then add 14 on both sides so it cancels out 22 plus 14 is 36
So J would equal 36
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Multiply.<br><br> 17.22⋅(−2.4)<br><br> Enter your answer in the box.
aleksandrvk [35]

Answer:

-41.328

Step-by-step explanation:

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Mary is 19 years old. she drinks the recommended intake of 2.2 liters of water and other beverages a day. about how many cups is
Veronika [31]
<span>We will consider that the average volume of a cup is 200 ml, that is 0,2 liters. That means 1 liter of liquid in cups is: 1 liter * 0.2 cup/liter = 5 cups Then the equivalent of recommended liquid in number of cups is: 2.2 litres * 5 cup / liter = 11 cups of 200 ml each.</span>
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4 years ago
Someone anybody please help
babymother [125]
This is a system of equations problem that can be solved using one of three methods: <span>graphing, substitution, or <span>elimination. I'll be using substitution.

In substitution:
1) S</span></span><span>olve one equation for either variable. I'll use the first equation because its easier to solve for one of the variables. I'll be solving for y because that will allow us to solve for the value of x faster.
</span>x+y=60
y=60-x

2) Substitute what you get into the other equation:
20x + 5y = 600
20x + 5(60-x) = 600

3) Solve your new equation in step 2 for the variable, x.
20x + 5(60-x) = 600
20x + 300-5x = 600
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There are D) 20 $20 bills in her drawer. 

3 0
3 years ago
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
Valentin [98]

Answer:

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324 \approx 4.3

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

Step-by-step explanation:

Data: 10,9,20,13,12

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,4)".And we see that t_{\alpha/2}=4.604

Now we have everything in order to replace into formula (1):

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

6 0
3 years ago
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