solve for x. −ax 3b > 5 x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negat
ive a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a
2 answers:
Answer:
Option (d) is correct.
x < the quantity negative 3 times b plus 5 all over negative a
Step-by-step explanation:
Given : -ax + 3b > 5
We have to solve for x and choose for the correct option from the given options.
Consider -ax + 3b > 5
Subtract 3b both side, we have,
-ax + 3b - 3b > 5 - 3b
Simplify , we have,
-ax > 5 - 3b
Divide both side by -1,

Divide both side by a , we get,

or same as
Thus, x < the quantity negative 3 times b plus 5 all over negative a
-ax + 3b > 5
Subtract 3b: -ax > 5 -3b
Diuvide by - a, which implies to change the sign > to <:
x < [5 -3b]/ (-a) or x < [3b - 5]/a ..... both are equivalent
That is second option.
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