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2 years ago

The equation of a parabola is y=x2+8x+16. Write the equation in vertex form.

Mathematics

1 answer:

lesya [120]2 years ago

8 0

Answer:

y = (x + 4)^2 + 0

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Find the equation of the linear function represented by the table below in slope-intercept form.

Y_Kistochka [10]

Answer:

y= 8x +7

Step-by-step explanation:

<u>slope-intercept form:</u>

y= mx +c, where m is the gradient (or slope) and c is the y-intercept.

Since it is a linear function, the gradient of any 2 points would be equal.

$gradient = \frac{y1 - y2}{x1 - x2}$

Thus, gradient of the line

$= \frac{39 - 23}{4 - 2} \\ = \frac{16}{2} \\ = 8$

Subst. m=8 into the equation:

y= 8x +c

To find the value of c, substitute a pair of coordinates.

When x=0, y= 7,

7= 8(0) +c

c= 7

Thus, the equation of the linear function is y= 8x +7.

3 0

3 years ago

Statements Reasons

Otrada [13]

Answer:

Step-by-step explanation:

6 0

3 years ago

Which inequality is true when x=7?

a_sh-v [17]

Answer:

11 - x <_ 18

11 - 7 <_ 18

4 <_ 18 (4 is less than or equal to 18)

7 0

3 years ago

What is the inverse of the function

sleet_krkn [62]

Answer:

$x^2-10x+31$

Step-by-step explanation:

$y=\sqrt{x-6}+5$

$x=\sqrt{y-6}+5$

$\sqrt{y-6}+5=x$

$\sqrt{y-6}+5-5=x-5$

$\sqrt{y-6}=x-5$

$\left(\sqrt{y-6}\right)^2=\left(x-5\right)^2$

$\left(\sqrt{y-6}\right)^2$

$=\left(\left(y-6\right)^{\frac{1}{2}}\right)^2$

$=y-6$

$\left(x-5\right)^2$

$=x^2-10x+25$

$y-6=x^2-10x+25$

$y-6+6=x^2-10x+25+6$

$y=x^2-10x+31$

6 0

3 years ago

Help me please this is probably very easy but I'm struggling

Lana71 [14]

I think it is 110 or
130

5 0

3 years ago