That's a quadratic, a nice parabola in vertex form.
The parabola has a positive x^2 term, so it's a CUP, concave up positive. It will have a minimum at the vertex, which is (2,5). Plot that point.
Now we need a couple of guide points to draw the usual parabola going up from both sides of its vertex. We try x=0 giving (0,9) and see that x=4 also gives 9, (4,9). Plot the parabola through those two points and the vertex and you're done.
Given:
is subtracted from 3.
To find:
The result of the given statement in the standard form of the polynomial.
Solution:
We need to find the result when
is subtracted from 3.
So, the resulted polynomial can be written as:

On simplification, we get
![[\because (a+b)^2=a^2+2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5D)
Therefore, the resulted polynomial in standard form is
.
Answer:
Shifted 5 unit right side then stretched vertically by the factor 100
Step-by-step explanation:
Here, parent function,
Transformed function,

Since, if a function f(x) gives cf(x), where c is any number,
Then the function was vertically stretched by factor c,
While, the function gives f(x-c),
Then the function was shifted c unit right.
Hence, the graph of
was shifted 5 unit right side then stretched vertically by the factor 100 to create the graph of 
Answer:
73 degrees
Step-by-step explanation: