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Dovator [93]
3 years ago
15

Find the real number between 6 4/9 and 6 8/9. Can someone please help me?

Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0

I am not completely sure but 2.7 because I subtracted the 6 8/9 by 6 4/9 and got 8/3 which then I dived and got 2.66666666666667

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If f(x) =7x+5/3-x, then show that fof power -1(x) is an identity function ​
Irina-Kira [14]

If f(X)= 7x +5/3 - x =6x +5/3

y= 6x +5/3

6x= y-5/3

f^-1(y)=x=(y-5/3)/6

So we can write

f(f^-1(y))= f((y-5/3)/6) = 6 (y-5/3)/6 +5/3= y-5/3+5/3= y

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Sue uses 3.75 meters of string to tie 3 balloons. she has 25 balloons to tie. how much string does she need.
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8 0
3 years ago
The sides of a quadrilateral are 3, 4, 5, and 6. Find the length of the shortest side of a similar quadrilateral whose area is 9
Georgia [21]

Answer:

9 units.

Step-by-step explanation:

Let us assume that length of smaller side is x.

We have been given that the sides of a quadrilateral are 3, 4, 5, and 6. We are asked to find the length of the shortest side of a similar quadrilateral whose area is 9 times as great.

We know that sides of similar figures are proportional. When the proportion of  similar sides of two similar figures is \frac{m}{n}, then the proportion of their area is \frac{m^2}{n^2}.

We can see that length of smaller side of 1st quadrilateral is 3 units, so we can set a proportion as:

\frac{x^2}{3^2}=\frac{9}{1}

\frac{x^2}{9}=\frac{9}{1}

x^2=9\cdot 9

x^2=81

Take positive square root as length cannot be negative:

\sqrt{x^2}=\sqrt{81}

x=9

Therefore, the length of the shortest side of the similar quadrilateral would be 9 units.

4 0
3 years ago
Read 2 more answers
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