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Anuta_ua [19.1K]
3 years ago
10

Please help look at picture​

Chemistry
1 answer:
Elena-2011 [213]3 years ago
7 0

Formation

1, 2, 5, 8, 9, 10, 11, 24, 28, 34

Single Replacement

14, 15*, 25, 32

Double Replacement

7, 13, 16, 17, 18, 26*, 30, 33, 35

Combustion

6, 19, 20, 21

Decomposition

3, 4, 12, 22, 23, 27, 29, 31

*I'm unsure of these two

1) 2 1 2                14) 2 3 2 3                  27) 1 1 1

2) 3 2 2              15) 2 2 2 1                   28) 4 6 1 2

3) 2 4 3              16) 2 3 2 3                  29) 1 12 11

4) 2 2 3              17) 3 2 1 6                   30) 2 1 2 1

5) 1 8 8               18) 3 1 1 3                    31) 1 1 1

6) 2 7 4 6           19) 1 5 3 4                   32) 1 2 2 1

7) 1 3 2 3            20) 2 5 4 2                 33) 1 2 1 2

8) 1 5 2               21) 2 15 12 6               34) 2 1 2

9) 1 6 1 8             22) 2 2 1                     35) 1 1 1 1

10) 2 3 2             23) 2 4 3

11) 4 3 2              24) 4 3 2

12) 2 2 3             25) 1 4 2 2

13) 1 2 1 2            26) 1 2 1 1 1

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Percent composition of Mg(OH)2​
LuckyWell [14K]

Answer:

The composition of Mg(OH)2 is

41.67 % Mg,

54.87 % O

3.457 % H

Explanation:

Thats the percent composition for each one in your question

4 0
2 years ago
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The total energy of a system remains
Lelu [443]
The total energy of a system remains constant.
3 0
3 years ago
Please help Physical Science! Pretty easy.
Alina [70]
A. I think the water may either rise up or it could leak out into the pie pan.

B. The air pressure would increase inside the glass, because you're adding a large amount of air into it.
6 0
4 years ago
A solution is 5.00% potassium chloride by mass. How much potassium chloride would you expect to collect by evaporating 150.0 g o
stepan [7]

Answer:

C. 7.50g

Explanation:

The percent (%) by mass of a solute in a solution refers to the number of grams contained in 100g of solution by that solute. In this case, 5% by mass of pottasium chloride (KCl) means 5g of KCl is contained in 100g of solution.

Therefore, in 150g of solution, there would be:

5g/100g × 150g

= 0.05 × 150

= 7.50g of KCl solute.

Hence, 7.50g of pottasium chloride would be expected to be collected by evaporating 150.0 g of the solution.

8 0
3 years ago
How many grams of oxygen gas are contained in a 15 L sample at 1.02 atm and 28°C? Please show your work.
vampirchik [111]

Answer:

0.019 g.

Explanation:

  • Firstly, we need to find the no. of moles of oxygen gas:
  • We can use the general law of ideal gas: <em>PV = nRT. </em>

where, P is the pressure of the gas in atm (P = 1.02 atm).

V is the volume of the gas in L (V = 15.0 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 28°C + 273 = 301.0 K).

∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.

  • To find the mass of oxygen gas, we have:

<em>no. of moles = mass/molar mass.</em>

<em></em>

∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.

4 0
4 years ago
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