Question

Percent composition of Mg(OH)2​

Answer 1

Answer:

Hello! The answer to your question is:

Mg: 41.68%

O2: 54.86%

H2: 3.46%

Explanation:

We need to find the percent composition of each element, so first, we need to find the molar mass. This is calculated by using the number underneath the element. The "2" outside of the parentheses is distributed to Oxygen and Hydrogen as well-meaning that you multiply the number by 2:

Mg: 24.31 g/mol

O2: 16.00 × 2 = 32.00 g/mol

H2: 1.01 × 2 = 2.02 g/mol

Now, we have to add up the molar mass of each element:

24.31 g/mol + 32.00 g/mol + 2.02 g/mol = 58.33

To find the percent composition of each element, you have to divide the molar mass of each element by the total molar mass:

Mg: $\frac{24.31 g/mol}{58.33 g/mol} \\= 41.68 percent$

O2: $\frac{32.00 g/mol}{58.33 g/mol} \\= 54.86 percent$

H2: $\frac{2.02 g/mol}{58.33 g/mol} \\= 3.46 percent$

The percent composition of each element is:

Mg: 41.68%

O2: 54.86%

H2: 3.46%

Answer 2

Answer:

The composition of Mg(OH)2 is

41.67 % Mg,

54.87 % O

3.457 % H

Explanation:

Thats the percent composition for each one in your question