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natka813 [3]
3 years ago
6

Fraction math problems, have lots tonight need help for some

Mathematics
1 answer:
Vanyuwa [196]3 years ago
7 0

Answer:

5

Step-by-step explanation:

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22 more than four times a number is less than 82 <br><br> (Inequality equation)
Tanzania [10]

22^4c-82. Is the equation I think you are looking for.

5 0
4 years ago
The amount of money spent on textbooks per year for students is approximately normal.
Ostrovityanka [42]

Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       \r p  =  \frac{210}{500}

       \r p  = 0.42

Given that the confidence level is 0.99 the level of significance is  \alpha =  0.01

The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

  Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} }*  \sqrt{ \frac{\r p (1- \r p )}{n} }

=>   E =  0.42 *  \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }

=>     E =  0.0093

The 99% confidence interval  is

     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

4 0
4 years ago
Please help ASAP I NEED THIS TOMORROW!!!
Mama L [17]
She will pay 90 because the income is 5 times greater
(answer o number one)
7 0
3 years ago
What is the total amount and the amount of interest earned on $6,500 at 6% for 25 years?
Deffense [45]
Here's the equation for one year:
0.06(6500) + 6500
But because it is 25 years:
25(0.06(6500)) + 6500
1.5(6500) + 6500
We can make it simpler:
2.5(6500)
The total amount is $16350
3 0
3 years ago
WILL GIVE BRAINLIEST AND 13 POINTS!!!!!! When you measure the length of an object to the eighth of an inch and again to the four
Savatey [412]

The smaller the value of the least increment, the more precise a number is.

Length measured to the nearest 1/8 inch will be more precisely specified than length measured to the nearest 1/4 inch.

_____

In general, precision has little to do with accuracy—how close the measured value is to the actual value. A measurement can be very precise, but just plain wrong. (Many electronic instruments have resolution (precision) that exceeds their accuracy. That is, one or two (or more) of the least-significant displayed digits may be in error.)

7 0
3 years ago
Read 2 more answers
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