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1 year ago

Reflection across y = -x please I need help I will mark you brainless

Mathematics

1 answer:

tresset_1 [31]1 year ago

4 0

Answer is
U= (-2,2)
V=(-2,4)
W= (-4,3)

Step by step
Find points for the triangle.
Using the rule for reflection across y axis.

The rule for a reflection over the y -axis is (x,y)→(−x,y)

U (2,2) ➡️ (-2,2)

V (2,4) ➡️ (-2,4)

W (4,3) ➡️ (-4,3)

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Solve the following equation: x^3 -168 = [24(x-2)] / 2 PLEASE REPLY ASAP

Nataly_w [17]

Hi Larry

x^3 - 168 = [ 24(x-2)] / 2
x^3 - 168 = (24x - 48)/2
x^3 - 168 = 12x - 24
Subtract 12x - 24 to both sides
x^3 - 168 - (12x - 24) = 12xx - 24 - (12x - 24)
x^3 - 12x - 144 = 0
Now, factor the left sides
(x - 6)(x^2 + 6x + 24) = 0
Set factors equal to 0
x - 6 = 0 or x^2 + 6x + 24 = 0
x = 0 + 6 or x^2 + 6x + 24 - 0
x = 6
Answer : X = 6

Good luck !

7 0

3 years ago

Find FD(round to the nearest tenth) please and thank you!

xxTIMURxx [149]

Answer:

FD = 25.9

Step-by-step explanation:

13x - 16 = 4x + 11

9x = 27

x = 3

using Pythagorean theorem:

FD² = 12² + [4(3) + 11]²

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FD = 25.94

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3 years ago

Which expressions are equivalent to 10 over 10 3/4?

worty [1.4K]

Answer:

There are no choices, but $\frac{10}{10.75}$ can be changes in the following ways: multiplying the numerator and the denominator by the same amount, or dividing the numerator and denominator by the same amount.

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3 years ago

Read 2 more answers

Can you do 2 problems? and then someone else do the other 2 ty!

Lynna [10]

Answer:

5.) MIGHT I SAID MIGHT be 20+16+12=48km squared for perimeter and 192 (im not sure really) for area

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Step-by-step explanation:

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2 years ago

The first eight quizzes in this class had average scores of 8,9,9,8,8,9,8,7. This gives a sample mean of 8.25 and a sample stand

alexira [117]

Answer:

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

t = 1.076

Step-by-step explanation:

Step(i):-

Given Mean of the Population (μ) = 8.0

Mean of the sample (x⁻) = 8.25

Given data

8,9,9,8,8,9,8,7

Given sample size n= 8

Given sample standard deviation(S) = 0.661

Step(ii):-

Null hypothesis : H: (μ) = 8.0

Alternative Hypothesis :H:(μ) > 8.0

Degrees of freedom = n-1 = 8-1=7

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{8.25 -8.0}{\frac{0.661}{\sqrt{8} } }$

t = 1.076

Critical value

t₍₇,₀.₀₅₎ = 2.3646

The calculated value t = 1.076 < 2.3646 at 0.05 level of significance

Null hypothesis is accepted

Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0

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3 years ago