Is Fe2+ + 2e- = Fe an oxidation or reduction

Why are coal, oil, and natural gas called fossil fuels?

sergeinik [125]

Because that's where they come from. Coal, oil, and natural gas are the products
of dead dinosaurs rotting in the ground under great pressure for millions of years.

6 0

3 years ago

Read 2 more answers

Help not to sure what its asking I thought it was 2 but there ain't a 2

Shtirlitz [24]

the answer is d. this is due to the fact a proton weighs 2000 times more then a electron

5 0

3 years ago

Read 2 more answers

What do ionic compounds form

Snowcat [4.5K]

Answer:

By the result of the formation of positive and negative ions, Ionic compounds are formed.

Explanation:

Electrons are actually transferred from one atom to another to form rare gas electron structures for each ion. The atom which forms a positive ion loses electrons to the atom which gains electrons to form a negative ion. A compound is not stable unless the number of electrons which are lost and gained are equal

3 0

4 years ago

What is the empirical formula for a compound that contains 79.86 % iodine and 20.14 % oxygen by mass?

serg [7]

Answer:

IO₂

Explanation:

We have been given the mass percentages of the elements that makes up the compound:

Mass percentage given are:

Iodine = 79.86%

Oxygen = 20.14%

To calculate the empirical formula which is the simplest formula of the compound, we follow these steps:

> Express the mass percentages as the mass of the elements of the compound.

> Find the number of moles by dividing through by the atomic masses

> Divide by the smallest and either approximate to nearest whole number or multiply through by a factor.

> The ratio is the empirical formula of the compound.

Solution:

I O

% of elements 79.86 20.14

Mass (in g) 79.86 20.14

Moles(divide by

Atomic mass) 79.86/127 20.14/16

Moles 0.634 1.259

Dividing by

Smallest 0.634/0.634 1.259/0.634

1 2

The empirical formula is IO₂

7 0

3 years ago

The activation energies are 45. 3 kj mol^-1 for k1 and 69. 8 kj mo1-1 for k2. If the rate constants are equal at 320 k, at what

Katyanochek1 [597]

At temperature 298K, the value of k1/k2 will equal to 2.00

According to Arrhenius's equation

Sometimes the Arrhenius equation is written as k = Ae- $^{E/RT}$ , where k is the rate of the chemical reaction, A is a constant that varies depending on the chemicals involved, E is the activation energy, and R is the universal gas constant, and T is the temperature.

$\frac{k1}{k2} = \frac{A_{1} e^{-E_{a1}/ RT} }{A_{2} e^{-E_{a2}/ RT} }$

= $\frac{A1}{A2} e^{(E_{a2}-E_{a1)}/RT }$

Given

Eₐ₂ = 69.8 × 10³ J/mol

Eₐ₁ = 45.3 × 10³ J/mol

R = 8.314J/kmol³

Now if the rate constant is equal means K1/K2 = 1 at T = 320 K

So if we put the values of K1/K2, Ea2,Ea1, T, and R into the formula

On solving

We get

A1/A2 = 1.001 × 10⁻⁴

Now when K1/K2 = 2

Then if we put the value of A1/A2, Ea1, Ea2, R, K1/K2 in the same equation,

On solving we get

T = 298 K

Hence, At temperature 298K k1/k2 will equal to 2.00

Learn more about Arrhenius's equation here brainly.com/question/26724488

#SPJ4

5 0

2 years ago