Taking into account the reaction stoichiometry, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.
In first place, the balanced reaction is:
2 HgO → 2 Hg + O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- HgO: 2 moles
- Hg: 2 moles
- O₂: 1 moles
The molar mass of the compounds is:
- HgO: 216.59 g/mole
- Hg: 200.59 g/mole
- O₂: 32 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- HgO: 2 moles× 216.59 g/mole= 433.18 grams
- Hg: 2 moles× 200.59 g/mole= 401.18 grams
- O₂: 1 mole× 32 g/mole= 32 grams
Then the following rule of three can be applied: if by reaction stoichiometry 32 grams of O₂ are produced by 2 moles of HgO, 250 grams of O₂ are produced from how many moles of HgO?

<u><em>moles of HgO= 15.625 moles≅ 15.63 moles</em></u>
Finally, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.
Learn more about reaction stoichiometry:
Convert the amount of substance in carat to grams.
(5.0 carat) x (0.200 g / 1 carat) = 1 g
The volume of the substance is obtained by dividing the mass by the density,
v = m / d
v = 1 g / (3.51 g/cm³) = 0.2849 cm³
Therefore, the volume of a 5.0 carat diamond is approximately 0.285 cm³.
Answer:
[Ar] 4s2 3d10 4p3
Explanation:
Arsenic is Element 33. It is the 15th element in the Fourth Row, following the noble gas Ar at the end of the Third Row.
Thus, its noble gas electron configuration is
[Ar] 4s2 3d10 4p3
Answer:
The theoretical yield of Cu(s) in moles is 60.15 moles
Explanation:
Step 1: Data given
Number of moles CuO = 70.8 moles
Number of moles NH3 = 40.1 moles
Molar mass CuO = 79.545 g/mol
Molar mass NH3 = 17.03 g/mol
Step 2: The balanced equation
3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles
There will remain 70.8 - 60.15 = 10.65 moles CuO
Step 3: Calculate moles Cu
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
For 40.1 moles NH3 we'll have 60.15 moles Cu
The theoretical yield of Cu(s) in moles is 60.15 moles
Answer:
false
salt water does the oppsotie
Explanation: