Which element has only two half filled orbitals in the 3D sub level ?
ANSWER:
Titanium
Answer is 273
explanation:
The rule of division for significant figures is to put the answer to the least amount of significant figures presented in the problem.
0.0131 only has 3 sig figs which is 131
3.582 has 4 sig figs
The least amount is 3 in the problem
When you originally divide 3.582 and 0.0131 you get 273.4531 in your calculator
Now put it to 3 sig figs
4 is not greater than 5 so you don't need to round
273 is 3 sig figs.
So answer is 273
Answer:
The answer is: +7
Explanation:
Oxidation state or oxidation number of an element is the hypothetical charge on an element that forms completely ionic bonds. The oxidation number represents the number of electrons lost or gained by that element.
Perchlorate ion is a molecule with a chemical formula: ClO₄⁻
The oxidation state of oxygen in ClO₄⁻ = -2,
the total charge on the ClO₄⁻ molecule = -1,
let the oxidation state of chlorine be x
<u><em>As the sum of oxidation states of all elements in a molecule is equal to the total charge on the molecule.</em></u>
⇒ oxidation state of chlorine + oxidation state of oxygen × 4 = total charge on the molecule
⇒ x + (-2) × 4 = -1
⇒ x + (-8) = -1
⇒ x = -1 + 8 = +7
⇒<u> </u><u>x = +7</u>
<u>Therefore, the oxidation state of chlorine in the perchlorate ion (ClO₄⁻): x = +7</u>
Answer:
a. Values are - (1) 3,1,-1,1/2 (2) 2,1,-1,-1/2 (3) 3,0,0,1/2 (4) 4,3,3,-1/2
(5) 3,2,2,1/2
b. Order be- I > Sn > Xe
Explanation:
a.
Valid quantum numbers are -
'l' value should be less than 'n' value and 'ml' value should be '-l' to 'l'
'ml' value should not more than 'l' or 'n'.
Values are -
3,1,-1,1/2
2,1,-1,-1/2
3,0,0,1/2
4,3,3,-1/2
3,2,2,1/2
b.
Given that-
I [Kr]4d¹⁰5s²5p⁵
Sn [Kr]4d¹⁰5s²5p²
Xe [Kr]4d¹⁰5s²5p⁶
Order be-
I > Sn > Xe
Xe is least because it is completely filled outer shell (5s²5p⁶
