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Inga [223]
4 years ago
6

An airplane is flying 600 mph on a horizontal path that will take it directly over an observer. The airplane remains a constant

altitude of 7 miles. What is the rate of change of the distance between the observer and the airplane when X = 5 miles?
Mathematics
1 answer:
dezoksy [38]4 years ago
5 0
<h2>Change of the distance between the observer and the airplane when X = 5 miles is 348.84 mph</h2>

Step-by-step explanation:

We have by Pythagoras theorem

       Distance between the observer and the airplane² = Horizontal distance² + Altitude²

        d² = h² + a²

Here we have

          h = X = 5 miles

          a = 7 miles

          d² = 5² + 7²  = 74

          d =8.60 miles

          \frac{dh}{dt}=600mph\\\\\frac{da}{dt}=0

Differentiating d² = h² + a² with respect to time

            2d\frac{dd}{dt}=2h\frac{dh}{dt}+2a\frac{da}{dt}\\\\8.60\frac{dd}{dt}=5\times 600+7\times 0\\\\\frac{dd}{dt}=348.84mph

Change of the distance between the observer and the airplane when X = 5 miles is 348.84 mph

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