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Lilit [14]
3 years ago
7

52 = 1/2x + 15 - 3.25x - 7please show step by step !! ​

Mathematics
1 answer:
Mariulka [41]3 years ago
8 0

Answer:

x = -16

Step-by-step explanation:

52= 1/2x+15−3.25x−7

Combine 1/2x and −3.25x to get −11/4 x.

52= −11/4x+15−7

Subtract 7 from 15 to get 8.

52=−11/4x+8

Swap sides so that all variable terms are on the left hand side.− 11/4x+8=52

Subtract 8 from both sides.

− 11/4x=52−8

Subtract 8 from 52 to get 44.

−11/4 x=44

Multiply both sides by − 4/11

​ the reciprocal of − 11/4

​x=44(−4/11)

​Express 44(−4/11 ) as a single fraction.

x= 44(−4)

​Multiply 44 and −4 to get −176.

x= −176/11

​Divide −176 by 11 to get −16.

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Calculus graph please help
tresset_1 [31]

Answer:

See Below.

Step-by-step explanation:

We are given the graph of <em>y</em> = f'(x) and we want to determine the characteristics of f(x).

Part A)

<em>f</em> is increasing whenever <em>f'</em> is positive and decreasing whenever <em>f'</em> is negative.

Hence, <em>f</em> is increasing for the interval:

(-\infty, -2) \cup (-1, 1)\cup (3, \infty)

And <em>f</em> is decreasing for the interval:

\displaystyle (-2, -1) \cup (1, 3)

Part B)

<em>f</em> has a relative maximum at <em>x</em> = <em>c</em> if <em>f'</em> turns from positive to negative at <em>c</em> and a relative minimum if <em>f'</em> turns from negative to positive to negative at <em>c</em>.

<em>f'</em> turns from positive to negative at <em>x</em> = -2 and <em>x</em> = 1.

And <em>f'</em> turns from negative to positive at <em>x</em> = -1 and <em>x</em> = 3.

Hence, <em>f</em> has relative maximums at <em>x</em> = -2 and <em>x</em> = 1, and relative minimums at <em>x</em> = -1 and <em>x</em> = 3.

Part C)

<em>f</em> is concave up whenever <em>f''</em> is positive and concave down whenever <em>f''</em> is negative.

In other words, <em>f</em> is concave up whenever <em>f'</em> is increasing and concave down whenever <em>f'</em> is decreasing.

Hence, <em>f</em> is concave up for the interval (rounded to the nearest tenths):

\displaystyle (-1.5 , 0) \cup (2.2, \infty)

And concave down for the interval:

\displaystyle (-\infty, -1.5) \cup (0, 2.2)

Part D)

Points of inflections are where the concavity changes: that is, <em>f''</em> changes from either positive to negative or negative to positive.

In other words, <em>f </em>has an inflection point wherever <em>f'</em> has an extremum point.

<em>f'</em> has extrema at (approximately) <em>x</em> = -1.5, 0, and 2.2.

Hence, <em>f</em> has inflection points at <em>x</em> = -1.5, 0, and 2.2.

7 0
3 years ago
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arsen [322]
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