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Ber [7]
3 years ago
12

A coin is tossed 15 times the result was 9 heads and 6 tails what is the theoretical probability of tails

Mathematics
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer:

50% chance because there is 2 sides heads and Tails so u have a 50% chance of heads and 50% chance of Tails

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Step-by-step explanation:

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2 years ago
Calculate S_24 for the arithmetic squence in which a_13= 1.9 and the common difference is d=3.7
zloy xaker [14]

Answer:

D. 1.2

Step-by-step explanation:

The sum of an arithmetic sequence is the product of the average term value and the number of terms.

The average term is often computed by averaging the first and last terms of the sequence. It can also be computed by averaging the middle two terms of the sequence (when there are an even number of terms, as here).

We are given a_13 is 1.9. We know that a_12 is 3.7 less, so is -1.8. Then the average of these two middle terms is ...

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The product of this value and the number of terms (24) is ...

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Find the value of the constant m √150 - √12m + √54 = 0​
Tomtit [17]

Answer:

<u>m</u><u> </u><u>is</u><u> </u><u>√</u><u>2</u>

Step-by-step explanation:

{ \tt{ \sqrt{150}  -  \sqrt{12}m +  \sqrt{54}  = 0 }} \\ { \tt{ \sqrt{12}m } =  \sqrt{150}  -  \sqrt{54} } \\ { \tt{ (\sqrt{4 \times 3}) m = ( \sqrt{25 \times 6} ) - ( \sqrt{9 \times 6}) }} \\ { \tt{( \sqrt{4 \times 3} )m = 5 \sqrt{6}  - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3}m = 5 \sqrt{6}   - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3} m = 2 \sqrt{6} }} \\ { \tt{ \sqrt{3}  m =  \sqrt{6} }} \\ { \tt{ \sqrt{3} m = ( \sqrt{3} \times  \sqrt{2} ) }} \\ { \tt{m =  \sqrt{2} }}

7 0
3 years ago
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