4 x
5 20
80/5=16
20(total questions)/5(total questions, simplified)=4
Multiply 4 by 4(correct questions).
The second method is better for a student in elementary!
The answer is No solution
Isn't that interesting? What a neat little problem.
The middle number between a and b = (a + b)/2
The middle number between b and c = (b + c) / 2
The middle number between c and d = (c + d)/2
The middle number between d and a = (d + a)/2
The sum of the numbers in the corners of
diagram 1 = a + b + c + d Do you agree.
Now look at diagram two. Start by putting a, b, c and d in the corners.
Now remove the brackets from what I found above.
diagram 2 = a/2 + b/2 + b/2 + c/2 + c/2 + d/2 + d/2 + a/2 Now collect all the like terms.
<em>diagram 2 = a/2 + a/2 + b/2 + b/2 + c/2 + c/2 + d/2 + d/2</em>
<em>a/2 + a/2 = a does it not?</em>
<em>b/2 + b/2 = b</em>
<em>c/2 + c/2 = c</em>
<em>d/2 + d/2 = d</em>
<em>The sum of the middle numbers in diagram 2 = a + b + c + d</em>
<em>But that's the same sum as diagram 1, which was what you were asked to prove. </em>You cannot come up with a counter example that will give a different result, at least in the positive integers.
The question provides you with room for a written answer. You are going to have to reproduce in some form what I've put in italics.
Thank you for posting.
When answering, you can press crtl + i <em>and from that point on you will type using italics</em>.
You can also highlight a section of text that you want to <em>italicize</em>. This can be used to italicize words that you forgot to <em>italicize </em>while you were typing.
54 are left for your questiom
