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Vaselesa [24]
2 years ago
6

Combine gas law: PV/T=k or (P1V1)/T1=(P2T2)/T2

Chemistry
2 answers:
tangare [24]2 years ago
6 0

Answer:

A and C

Explanation:

I took the test

dedylja [7]2 years ago
4 0

The containers that have equal pressures are Container A and Container C

<h3>Gas Laws</h3>

From the question, we are to determine which containers have equal pressures.

Using the ideal gas law equation, we will determine the containers that have equal pressures.

From the ideal gas equation, we have

PV = nRT

Where,

P is the pressure

V is the volume

n is the number of moles

R is the gas constant

and T is the temperature

Then,

P = \frac{nRT}{V}

  • Container A

n = 0.5 mole

V = 11.2 L

P = \frac{0.5 \times RT}{11.2}

P = 0.04464RT

  • Container B

n = 2 moles

V = 22.4 L

P = \frac{2 \times RT}{22.4}

P = 0.0892857RT

  • Container C

n = 1 mole

V = 22.4 L

P = \frac{1\times RT}{22.4}

P = 0.04464RT

  • Container D

n = 2 mole

V = 11.2 L

P = \frac{2 \times RT}{11.2}

P = 0.17857RT

From above, we can observe that Container A and Container C have equal pressures. P = 0.04464RT

Hence, the containers that have equal pressures are Container A and Container C.

Learn more on Gas laws here: brainly.com/question/25736513

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A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix
Alisiya [41]

Answer:

M_f=38.8\%

Explanation:

From the question we are told that:

Pressure P=747mmHg

Temperature T=298K

Volume V=11.1

Heat Produced Q=780kJ

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 n= (747/760) *11.1/ (0.0821*298)

 n=0.446mol

Therefore

 x+y=0.446

 x=0.446-y .....1

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

 x(889) + y(2220) = 760 ...... 2

Comparing Equation 1 and 2 and solving simultaneously

 x=0.446-y .....1

 x(889) + y(2220) = 760 ...... 2

 x=0.173

 y=0.273

Therefore

Mole fraction 0f Methane is mathematically given as

 M_f=\frac{x}{n}*100\%

 M_f=\frac{1.173}{0.446}*100\%

 M_f=38.8\%

7 0
3 years ago
G(1)=0 g(n) =g(n-1)+n g(2)=
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G(2)=2

For this, you can plug in 2 everywhere you see an n. So the equation will read:
g(2)=g(2-1)+2 -> g(2)=g(1)+2. Since we are given g(1)=0, we can plug in 0 where we see g(1). The equation is now. g(2)=0+2. So, g(2)=2.
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Two liters of hydrogen gas are stored at a
Tju [1.3M]

Answer:

the volume will expand

Explanation:

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Answer:

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Explanation:

  • From the solubility curve that is shown in the attached image, the solubility of KCl per 100.0 g of water is about 50.0 g.
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