Answer:
3.125 × 10¹³ Electrons
Explanation:
Data provided in the question:
Charge per unit length on rod = 0.00500 C/m
Length of the rod = 1 mm = 1 × 10⁻³ m
Therefore, the total charge on the rod
= Charge per unit length on rod × Length of the rod
= 0.00500 C/m × ( 1 × 10⁻³ m)
= 5 × 10⁻⁶ C
Thus,
Number of electrons removed
= total charge on the rod ÷ Charge of an electron
= 5 × 10⁻⁶ ÷ (1.6 × 10⁻¹⁹)
= 3.125 × 10¹³ Electrons
Answer:
The percent abundance of oxygen-18 is 1.9066%.
Explanation:
The average atomic mass of oxygen is given by:
Where:
m: is the atomic mass
%: is the percent abundance
Since the sum of the percent abundance of oxygen isotopes must be equal to 1, we have:
Hence, the percent abundance of O-18 is:
Hence, the percent abundance of oxygen-18 is:
Therefore, the percent abundance of oxygen-18 is 1.9066%.
I hope it helps you!
Answer:
Metals are good conductors of heat and electricity, and are malleable (they can be hammered into sheets) and ductile (they can be drawn into wire). Most of the metals are solids at room temperature, with a characteristic silvery shine (except for mercury, which is a liquid). Nonmetals are (usually) poor conductors of heat and electricity, and are not malleable or ductile; many of the elemental nonmetals are gases at room temperature, while others are liquids and others are solids.
Explanation:
Answer: 3
Explanation: I took the k12 quiz
You have to use density=mass/volume formula:
Solve for x and you get
2282.75 grams
