1 year ago

My last question its easy but i dont get it lol help plz

Chemistry

2 answers:

pashok25 [27]1 year ago

8 0

There is no question on here lol

mr_godi [17]1 year ago

3 0

What is your question

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An aluminum can weighing 10 g absorbs 106.8 J of heat and warms by 12 degrees C. What is the specific heat of the aluminum can?

Sladkaya [172]

Answer:

$c_{Al} = 0.89\,\frac{J}{kg\cdot ^{\circ}C}$

Explanation:

The heating process is modelled after the First Law of Thermodynamics:

$Q = m \cdot c_{Al}\cdot \Delta T$

The specific heat of the aluminium can is:

$c_{Al} = \frac{Q}{m\cdot \Delta T}$

$c_{Al} = \frac{106.8\,J}{(10\,g)\cdot (12^{\circ}C)}$

$c_{Al} = 0.89\,\frac{J}{kg\cdot ^{\circ}C}$

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2 years ago

How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?

Naddik [55]

The solution for the question above is:

C = 0.270
V = 0.0275L 
n = ? 

Use the molar formula which is: C = n/V 
Re-arrange it to: n = CV 
n = (0.270)*(0.0275) 
n = 0.007425 mols 
(more precise) n = 7.425 x 10^-3 mols

7.425 x 10^-3 mols is the answer.

8 0

2 years ago

Converting 53.3g of oxygen to moles will give you???

Marat540 [252]

Answer:

3.33 mol

Explanation:

1 g of oxygen is 0.062502343837894 mol

53.3 * 0.062502343837894

3.3313749265597505 mol

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2 years ago

What are the purposes of a chemical equation? Check all that apply.

hjlf

The answer is the first one

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2 years ago

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A reaction that had two compounds as reactants and two compounds as products is most likely a

sergejj [24]

double-replacement reaction

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2 years ago