Answer:
True
Explanation:
According to Aufbau's principle "sublevels with lower energies are filled up before those with higher energies".
Sublevels do not fill up in numerical order but there is a certain manner in which they are filled. The pattern is shown below:
1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p e.t.c
We see that the 4s gets filled before the 3d sublevel.
Answer:
Theoretical yield for CO₂ is 5.10g
Explanation:
Reaction: 2C₆H₆(l) + 15O₂(g) → 12CO₂(g) + 6H₂O(g)
We convert the mass of oxygen to moles:
4.64 g /32 g/mol = 0.145 moles of O₂
Let's find out the 100% yield reaction of CO₂ (theoretical yield)
Ratio is 15:12. So let's make this rule of three:
15 moles of O₂ can produce 12 moles of CO₂
Therefore 0.145 moles of oxygen will produce (0.145 . 12) /15 = 0.116 moles
We convert the moles to mass: 0.116 mol . 44 g / 1mol = 5.10 g
You have 0.50 mol of NH3 and 0.20 mol of NH4+ to start (NH4Cl dissolves completely), given the molarity and 1.0 L solution.
30.0 mL of 1.0 M HCl is 0.0300 mol of HCl. This will react with the NH3 to produced 0.030 mol of NH4+.
You now have 0.47 mol NH3 and 0.23 mol NH4+. Now use the Henderson-Hasselbach equation to calculate your pH. The equation says to use concentration of acid and base, but you can just use the moles of them because it doesn’t make a difference.
pH = pKa + log(base/acid)
pKa = 14 - pKb = 14 - 4.75 = 9.25
pH = 9.25 + log(0.47/0.23) = 9.56
Answer:
416.876
Explanation:
Uhmm I am so so very sorry if this is incorrect
Answer:
2.5 mol/L
Explanation:
We'll begin by calculating the number of mole in 7 g of KOH. This can be obtained as follow:
Mass of KOH = 7 g
Molar mass of KOH = 39 + 16 + 1
= 56 g/mol
Mole of KOH =?
Mole = mass /molar mass
Mole of KOH = 7 / 56
Mole of KOH = 0.125 mole
Next, we shall convert 50 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
50 mL = 50 mL × 1 L / 1000 mL
50 mL = 0.05 L
Finally, we shall determine the molarity of the KOH solution. This can be obtained as follow:
Mole of KOH = 0.125 mole
Volume = 0.05 L
Molarity of KOH =?
Molarity = mole / Volume
Molarity of KOH = 0.125 / 0.05
Molarity of KOH = 2.5 mol/L
Thus, the molarity of the KOH solution is 2.5 mol/L
