Answer:
1.3 L
Explanation:
The volume of a rectangular cube can be calculated using the following formula:
Volume (L) = length (cm) x width (cm) x height (cm)
Keep in mind that 1 L = 1,000 cm³.
Before you can plug the values into the equation, you need to make sure they all have the same unit. Since the length is in meters (m), you need to first convert it to centimeters.
1 meter = 100 cm
0.159 m 100 cm
--------------- x ---------------- = 15.9 cm
1 m
Now, you can solve for the volume. To find the answer is the unit liters, you need to divide the volume by 1,000.
Volume = l x w x h
Volume = 15.9 cm x 10.5 cm x 7.7 cm
Volume = 1,285.5 cm³
Volume = 1.2855 L ------> Volume = 1.3 L
Answer:
315.
Explanation:
Hello.
In this case, since the given number has five significant figures as the zero is to the right of the first nonzero digit (3), if it is required to report it with three significant figures, it is necessary to "cut" it at the first five without any rounding since the subsequent zero is less than five.
Thus the number turns out:
315
Best regards.
For every 2 Mol NaOH you would get 1 Mol N2H4
Answer: pH of resulting solution will be 13
Explanation:
pH is the measure of acidity or alkalinity of a solution.
Moles of
ion = 
Moles of
ion = 

For neutralization:
1 mole of
ion will react with 1 mole of
ion
0.01 mol of
ion will react with =
of
ion
Thus (0.012-0.01)= 0.002 moles of
are left in 20 ml or 0.02 L of solution.
![[OH^-]=\frac{0.002}{0.02L}=0.1M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%5Cfrac%7B0.002%7D%7B0.02L%7D%3D0.1M)
![pOH=-log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E-%5D)
![pOH=-log[0.1]=1](https://tex.z-dn.net/?f=pOH%3D-log%5B0.1%5D%3D1)


Thus the pH of resulting solution will be 13
SAMPLE A - <span>pure substance.
</span>SAMPLE B - <span>homogeneous mixture.
</span>SAMPLE C - <span>heterogeneous mixture.
</span>Pure substance - <span>constant composition and properties.</span>
Homogeneous mixture - same uniform appearance and composition.
Heterogeneous mixture - <span>not </span>uniform<span> in composition, two phases (liquid and dust).
</span>