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antoniya [11.8K]
3 years ago
7

Hello I was wondering what is the m

Mathematics
1 answer:
oee [108]3 years ago
5 0
Angles in a triangle add up to 180 therefore:

Angle CAB = 180 - 60 - 50 = 70

Angles on a straight line add up to 180 therefore the missing angle is:

180 -70 = 110

Answer is D

I hope this has helped you today, please rate as brainliest if you think this helped you understand the question.

Have a great day!
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How do I do the metric system?
Anastasy [175]

Answer:

look it up

Step-by-step explanation:

5 0
3 years ago
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Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be model
ohaa [14]

Answer:

(2, 11/2)

Step-by-step explanation:

This is a vertical parabola; we know that because x is squared here, while y is not.  The standard equation of a vertical parabola with vertex (h,k) is

4p(y-k) = (x-h)^2, where p is the distance between the vertex and the focus.  Comparing

4p(y-k) = (x-h)^2 to

10(y-3)  = (x-2)^2, we see that 4p = 10.  Therefore, p = 10/4 = 5/2, which is the vertical distance between the focus and the vertex.

Since the coordinates of the vertex are easily read from the given equation

(x-2)^2=10(y-3):  (h,k) = (2, 3)

all we need to do is to add p (5/2) to the y-coordinate (3);

The focus is at (2, 3 + 5/2), or (2, 11/2).

3 0
3 years ago
Write an equation for an ellipse centered at the orgin, which has foci ( plus minus 3, 0) and co-vertices at (0, plus minus 4)
Vadim26 [7]

Answer:

The answer is below

Step-by-step explanation:

The co-vertices of an ellipse are the endpoints of the minor axis. The equation for an ellipse is given by:

\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2}=1

Where (h, k) is the center of the ellipse, (h, k±b) is the co-vertices, (h ± a, k) is the vertices, (h ± c, k) is the foci and c² = a² - b²

Since the center is the origin, hence (h, k) = (0, 0). i.e h = 0, k = 0.

Foci = (h ± c, k) = (± c, 0) = (±3, 0). c = 3

co-vertices = (h, k±b)  = (0, ±b)  = (0, ±4). b = 4

c² = a² - b²

a² = c² + b²

a² = 3² + 4² = 25

a = 5

Therefore the equation of the ellipse is:

\frac{x^2}{5^2} +\frac{y^2}{4^2}=1 \\\\\frac{x^2}{25} +\frac{y^2}{16}=1

6 0
3 years ago
PLEASE HELP!!!!!!!!!!<br> https://brainly.com/question/22588857
salantis [7]

Answer:

What do you need help with?

7 0
3 years ago
Factor completely: 8x5 + 28x4 + 12x3
bija089 [108]

Answer: The answer is 4x^3(x+3)(2x+1).


Step-by-step explanation: Given expression is

8x^5+28x^4+12x^3.

To factorise the given expression, first we need to take common the powers of 'x' which are common to all the three terms. Then, we need to factorise the remaining expression using the formula

x^2+(a+b)x+ab=(x+a)(x+b).

Let us start as follows

8x^5+28x^4+12x^3\\\\=4x^3(2x^3+7x+3)\\\\=4x^3(2x^3+6x+x+3)\\\\=4x^3\{2x(x+3)+1(x+3)\}\\\\=4x^3(x+3)(2x+1).

Thus, the required factorised expression is

4x^3(x+3)(2x+1).



3 0
4 years ago
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