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2 years ago

Find the selling price is a store pays $12 for a book and the markup is 25%.

Mathematics

2 answers:

Brut [27]2 years ago

8 0

Answer:

$15

Step-by-step explanation:

use a calculator and type 25%x12 and you will get 3

so 3 is 25% of 12

add 12 and 3 together to get your answer. $15

koban [17]2 years ago

5 0

Answer:

$15

Step-by-step explanation:

$12 + 25% = $15

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Write the equation in y-intercept form slope 2 passes through point (5,-2)

Alenkinab [10]

<h2>Answer</h2>

The equation is y = 2x - 12

<h2>Explanation</h2>

Equation in slope intercept form is

$y = mx + b$

Where,

m = slope

b = y-intercept

Putting the value of slope in this equation:

$y = 2x + b$

From this we can solve the equation for b

$b = y - 2x$

$b = -2 - 2(5)$

$b = -12$

Now, the equation of y-intercept becomes

$y = 2x - 12$

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3 years ago

Which system of equations does not have a real solution

Aloiza [94]

Answer:

the correct answer is y = x 2 + 3x - 5 and x + y = -10

Step-by-step explanation:

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3 years ago

In a group of dogs and their owners, there are exactly 20 heads and 64 legs. How many dogs are in the group

Juliette [100K]

Answer:

If we assume that everyone in the group is an owner, we would have

$20*2=40$ legs.

$64-40=24$ legs

Therefore, we need 24 more legs.

These 24 additional legs can be made from the difference of legs between the owners and dogs.

In this case, dogs have $4-2=2$ more legs than an owner.

24 ÷ 2 = 12.

There are 12 dogs in the group.

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2 years ago

If 3 people share 4 cookies equally how many cookies will they get

melamori03 [73]

Answer:

1.33333333

Step-by-step explanation:

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2 years ago

Read 2 more answers

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago