Graph y=-5x+4 please help, I have an iReady to do.

2) AY RA O positive zero O negative O undefined

bezimeni [28]

Answer:

negative

hope it helps;)

8 0

3 years ago

Read 2 more answers

Sin167cos107-cos167sin107

insens350 [35]

Sin 167 = 0.22495

cos 107 = -0.29237

cos 167 = -0.97437

sin 107 = 0.95630

(sin 167)(cos 107) - (cos 167)(sin 107)

(0.22495)(-0.29237) - ( -0.97437)(0.95630)

= 0.86602

hope this helps :)

6 0

3 years ago

3. About how much of the earth's surface is deserts?

Murrr4er [49]

Answer:

B- One-Quarter

Step-by-step explanation:

8 0

3 years ago

Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

Translation:

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

8 0

3 years ago

The basketball boosters are selling school t-shirts for 20 dollars and pants for 45 dollars. Last week they sold 100 items and c

lana66690 [7]

He sold 76 shirts and 24 pants.

Step-by-step explanation:

Given,

Cost of one t-shirt = $20

Cost of one pants = $45

Total items sold = 100

Total sales = 2600

Let,

x be the number of t-shirts

y be the number of pants

According to given statement;

x+y=100 Eqn 1

20x+45y=2600 Eqn 2

Multiplying Eqn 1 by 20

$20(x+y=100)\\20x+20y=2000\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(20x+45y)-(20x+20y)=2600-2000\\20x+45y-20x-20y=600\\25y=600$

Dividing both sides by 25

$\frac{25y}{25}=\frac{600}{25}\\y=24$

Putting in Eqn 1

$x+24=100\\x=100-24\\x=76$

He sold 76 shirts and 24 pants.

Keywords: linear equations, subtraction

Learn more about linear equations at:

#LearnwithBrainly

3 0

3 years ago