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amm1812
2 years ago
6

If a bloodstain has a length of 3.0cm and a width of 1.5cm what is the angle of impact?

Mathematics
1 answer:
zalisa [80]2 years ago
6 0

The angle of impact is 30°

<h3>What is the angle of impact?</h3>

In a bloodstain, the angle of impact can be used to determine the appearance of the resulting bloodstain if the bloodstain has a tail or pattern.

  • Bloodstain pattern analysis is the study of bloodstains at a scene of the crime in an attempt to reconstruct the events that resulted in the bloodshed.

Mathematically;

\mathbf{Angle  \ of \  impact = sin^{-1} (\dfrac{width \ stain}{length \ stain} )}

\mathbf{Angle  \ of \  impact = sin^{-1} (\dfrac{1.5}{3.0} )}

\mathbf{Angle  \ of \  impact = 30 ^0}

Learn more about the angle of impact here:
brainly.com/question/19423063

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Read 2 more answers
A rumor spreads through a small town. Let y(t) be the fraction of the population that has heard the rumor at time t and assume t
sladkih [1.3K]

Answer:

The answer is shown below

Step-by-step explanation:

Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.

a)

\frac{dy}{dt}\ \alpha\  y(1-y)

\frac{dy}{dt}=ky(1-y)

where k is the constant of proportionality, dy/dt =  rate at which the rumor spreads

b)

\frac{dy}{dt}=ky(1-y)\\\frac{dy}{y(1-y)}=kdt\\\int\limits {\frac{dy}{y(1-y)}} \, =\int\limit {kdt}\\\int\limits {\frac{dy}{y}} +\int\limits {\frac{dy}{1-y}}  =\int\limit {kdt}\\\\ln(y)-ln(1-y)=kt+c\\ln(\frac{y}{1-y}) =kt+c\\taking \ exponential \ of\ both \ sides\\\frac{y}{1-y} =e^{kt+c}\\\frac{y}{1-y} =e^{kt}e^c\\let\ A=e^c\\\frac{y}{1-y} =Ae^{kt}\\y=(1-y)Ae^{kt}\\y=\frac{Ae^{kt}}{1+Ae^{kt}} \\at \ t=0,y=10\%\\0.1=\frac{Ae^{k*0}}{1+Ae^{k*0}} \\0.1=\frac{A}{1+A} \\A=\frac{1}{9} \\

y=\frac{\frac{1}{9} e^{kt}}{1+\frac{1}{9} e^{kt}}\\y=\frac{1}{1+9e^{-kt}}

At t = 2, y = 40% = 0.4

c) At y = 75% = 0.75

y=\frac{1}{1+9e^{-0.8959t}}\\0.75=\frac{1}{1+9e^{-0.8959t}}\\t=3.68\ days

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