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2 years ago

A decimal in between 0.25 and 0.125

Mathematics

1 answer:

Olin [163]2 years ago

8 0

0.2 is a decimal between 0.25 and 0.125

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A chef has 6 jars of spices. How many ways can he line up the jars on his kitchen shelf? Show your work.

neonofarm [45]

6*6=36. he can line the jars pu 36 diff ways.

3 0

3 years ago

Read 2 more answers

Dan painted 3/4 of a wall using 1/4 of a can of paint.Select all statements that are true.

Juli2301 [7.4K]

Answer:

B, C, F

Step-by-step explanation:

3/4 is 3 times 1/4, so the number of walls Dan can paint is 3 times the number of cans Dan uses.

A. 1/2 can will paint 3/2 walls, not 2.

B. 1 can will paint 3 walls — true

C. 5/3 cans will paint 5 walls — true

D. 2 cans will paint 6 walls, not 8.

E. 5/2 cans will paint 15/2 = 7 1/2 walls, not 10.

F. 11/3 cans will paint 11 walls — true

5 0

3 years ago

.............................

goldfiish [28.3K]

It's B and C
hope this helps

4 0

3 years ago

Example on worksheet (subtracting by adding up)

Lisa [10]

Answer:

(49 - 29) + 1 =(50 - 29)

Step-by-step explanation:

The 20 comes from the subtraction of 29 in both sides of the previous step equality. In the following, I transcript the complete procedure and I add the step that you need to understand why 20 appears (in bold numbers):

29+20=49

49+1=50

(49 - 29) + 1 =(50 - 29)

20+1=21

50-29=21

hence, it was only nesseraty to subtract 29

3 0

3 years ago

A club consisting of 6 juniors and 8 seniors is to be formed from a group of 13 juniors and 16 seniors. How many different clubs

Vilka [71]

Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

$C = \frac{N!}{(N-K)!*K!}$

For the juniors we have N = 13 and K = 6

$Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716$

For the seniors we have N = 16 and K = 8

$Cs = \frac{16!}{8!8!} = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870$

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

5 0

3 years ago