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Llana [10]
2 years ago
13

A decimal in between 0.25 and 0.125

Mathematics
1 answer:
Olin [163]2 years ago
8 0
0.2 is a decimal between 0.25 and 0.125
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A rancher wishes to build a fence to enclose a rectangular pen having area 24 square yards. Along one side the fence is to be ma
Gnoma [55]

Answer:

The  value  is  C \approx \$76

Step-by-step explanation:

From the question we are told that

   The  area of the rectangular pen is  A =  24 \ yard^2

     The  cost of material used to make one side is  z = \$ 6

    The  cost of material used to make the other sides is  r  =  \$ 3

Now  , the fence to be build around the rectangular pen  has four sides, the first opposite sides are equal, let assume each of the to be x yard   and the other opposite sides are also equal as well let assume of the to be y yard

So the cost is mathematically represented as

       C =  zx  +  r (x + 2y )

=>   C =  6x  +  3(x + 2y)

=>   C =   9x  +  6y

Now the area of the fence is mathematically represented as

      A =  x* y =  24

=>    y  =  \frac{24}{x}

=>  C =   9x  +  6[\frac{24}{x} ]

=>   C =   9x  +  [\frac{144}{x} ]

Now differentiating

     C'  =  9 + 144*  (-2) x^{-2}

     C'  =  9 - 288x^{-2}

At minimum C' =  0

So  

     9 - 288x^{-2} =  0

     x^{-2} =  0.03125

    x =  \sqrt{\frac{1}{0.03125} }

    x =  5.66

Now substituting for x in the equation above to obtain minimum cost

       C =   9(5.66)  +  [\frac{144}{5.66} ]

       C \approx \$76

   

 

8 0
3 years ago
Please help with this I am very stuck because I am horrible at math
tigry1 [53]

Answer:

20

Step-by-step explanation:

6 0
3 years ago
How to do this problem
gavmur [86]
I forget sorry I’m very sorry I don’t even know elegy I commented
4 0
3 years ago
Find the perimeter.<br> 15 in.<br> 12 in.<br> 8 in.<br> 9 in.<br> 14 in.
ololo11 [35]

Answer:

58 inches

Step-by-step explanation:

In order to find the perimeter of a shape, you must add up the total length of all the sides. 15 inches + 12 inches + 8 inches + 9 inches + 14 inches = 58 inches.

7 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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