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ohaa [14]
2 years ago
6

the diagram shows a circle of radius 3cm drawn inside a square.write down the exact value of the following and state whether the

answer is rational or not
Mathematics
1 answer:
rewona [7]2 years ago
5 0

Answer:

The circumference of the circle

Step-by-step explanation:

You might be interested in
What is the interquartile range of the data ? 0,2,4,0,2,3,8,6
Alexeev081 [22]

(arrange the data set from least to greatest)

0, 0, 2, 2, 3, 4, 6, 8

(find the median: *the middle number*)

Median: 2.5

Lower quartile: 1

Upper quartile: 5

Interquartile range : upper quartile - lower quartile = answer

Interquartile range: 5 - 1 = 4

So the IQR or interquartile for the following data set is 4.

6 0
3 years ago
Please please help............
maksim [4K]
Part A Simplify:

Answer is - 12b + 6c + 18



Part B

Answer is (D)

Factor/simplify
- 12b + 6c + 18

6(- 2b + c + 3)
= (6)(- 2b + c + 3)
= (6)(- 2b ) + (6)(c) + (6)(3)
= - 12b + 6c + 18

therefore,- 12b + 6c + 18; Factored in GCF is 6(-2b + c + 3)





- 12b + 6c + 18
reorder the terms
18 + 12b + 6c

Factor out the GCF " 6"
6(3 + 2b + c)


Final Result:
6(3 + 2b + c)



Hope this helps
6 0
3 years ago
4. A picture frame is on sale for $16 off the original price. This is a 40% discount. What is the original price of the picture
sammy [17]

Answer:

$40

Step-by-step explanation:

this is not a mistake, it just turns out that 40% of 40 is 16

5 0
2 years ago
Jada has a sleeping bag that is rated for 30° F. This means that if the temperature outside is at least 30° F, Jada will be able
Likurg_2 [28]

Answer:

30-70 degrees F Actually read my response because it explains

Step-by-step explanation:

Well if the outside air is 30 degrees F and the rated temp. for the sleeping bag is 30 then the temp. for the sleeping bag has to be anywhere from 30 and up. Probably like 30 through 70. I didnt really know what the question was because you didn't really make it clear but I tried my best. :)

Hope this helps!!!!!

Pls mark brainliest

3 0
2 years ago
Write as a single logarithm 3-1/2(log6+log3-3log2)
faust18 [17]
3-\dfrac{1}{2}\left(\log6+\log3-3\log2\right)=\\
\log10^3-\dfrac{1}{2}\left(\log\left(6\cdot3\right)-\log2^3\right)=\\
\log1000-\dfrac{1}{2}\left(\log18-\log8\right)=\\
\log1000-\dfrac{1}{2}\left(\log\dfrac{18}{8}\right)=\\
\log1000-\dfrac{1}{2}\left(\log\dfrac{9}{4}\right)=\\
\log1000-\log\left(\dfrac{9}{4}\right)^{\dfrac{1}{2}}=\\
\log1000-\log\sqrt{\dfrac{9}{4}}=\\
\log1000-\log\dfrac{3}{2}=\\
\log\dfrac{1000}{\frac{3}{2}}=\\
\log\left(1000\cdot\dfrac{2}{3}\right)=\\
\log\dfrac{2000}{3}
6 0
2 years ago
Read 2 more answers
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