The flux of the given function f = x³i + y³j + z³k is given by f',
f' = 3(x²i + y²j + z²k)
Given, f = x³i + y³j + z³k
we have to find the flux of the given function f = x³i + y³j + z³k
On partial differentiating the function, we get
f' = 3x²i + 3y²j + 3z²k
f' = 3(x²i + y²j + z²k)
So, the flux of the given function f = x³i + y³j + z³k is given by f',
f' = 3(x²i + y²j + z²k)
Hence, the flux of the given function f = x³i + y³j + z³k is given by f',
f' = 3(x²i + y²j + z²k)
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1/3+4/5= 17/15
The commun multipleof 3 and 5 is 15.
1/3×5= 5/15
4/5×3= 12/15
5/12+12/15= 17/12
17/12×7= 119/84
119/84
Hope this helps! :)
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$ 624.14 because you cannot have more than 2 digits when you work with money
