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ohaa [14]
2 years ago
6

the diagram shows a circle of radius 3cm drawn inside a square.write down the exact value of the following and state whether the

answer is rational or not
Mathematics
1 answer:
rewona [7]2 years ago
5 0

Answer:

The circumference of the circle

Step-by-step explanation:

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Lim x>0- ((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX
Andre45 [30]
<span>((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX = (x^2 + 2x delta x + (delta x)^2 + x + delta x - x^2 - x) / delta x = delta x (2x + delta x + 1) / delta x = 2x + delta x + 1

Therefore, </span>Lim as x tends to 0 of <span>((x + delta X)^2 + x + deltaX - (x^2 + x)) / deltaX</span> = 1 + delta x
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3 years ago
What is 1/4x+1+3/4x-2/3-1/2x
Aleks04 [339]

Answer: 1/2x + 1/3

Step-by-step explanation:

Given:

1/4(x) + 3/4(x) - 1/2(x) + 1 - 2/3

Step 1: Combine like terms

1/4(x) and 3/4(x) have a common denominator of 4.  This means that you can add them together.

1/4(x) + 3/4(x) = 4/4(x) = x

Step 2: Find the common denominator of x in step 1 and combine like terms  

x - 1/2(x) = 2/2(x) - 1/2(x)

Now that we have the common denominator of x, we can combine like terms.  Its the same as adding or subtracting fractions without a variable.  In this case, you must subtract 1/2(x) from 2/2(x).

2/2(x) - 1/2(x) = 1/2(x)

Step 3: Find the common denominator of the constants and combine like terms

1 - 2/3 = 3/3 - 2/3

Now combine like terms.  Simply subtract 2/3 from 3/3.

3/3 - 2/3 = 1/3

Step 4: Write the simplified equation

1/2(x) + 1/3

This is the answer

4 0
2 years ago
What is the grates common factor of 16 and 48
lisabon 2012 [21]
The gcf of 16 and 48 is the largest positive integer that divides the numbers 16 and 48 without a remainder<span>. Spelled out, it is the greatest common factor of 16 and 48 Is what google says.</span>
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3 years ago
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UkoKoshka [18]

Answer:

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Step-by-step explanation:

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3 years ago
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A fish tank has the shape of a rectangular prism. It has a length of 2 1/4 meters, width of 7/8 meters, and a height of 1 1/2 me
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volume = L x W X H

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please mark brainliest

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