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3 years ago

How do you give an example for finding net force?

1 answer:

7 0

-- 6 people all trying to push a car out of snow

-- a Tug-o-War with 30 people of different sizes pulling on each end of the rope

-- you and your sister both pulling on the same doll (or Transformer)

-- lifting a book up from the table to a high shelf
taking a book down from a high shelf to the table
(one force is you; another force is gravity)

-- grabbing your big dog by his collar and trying to bring him inside

-- three people at the table all grab the ketchup bottle at the same time

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A chemical bond results from the mutual attraction of the nuclei for

GenaCL600 [577]

A chemical bond results from the mutual attraction of the nuclei for atoms and electrons.

Explanation:

Each atom tends to have an energy between the nuclei and electrons to keep it stable. So, there will be mutual attraction of the nuclei of atom and of electrons in the innermost shell to the outermost shell. And, this kind of mutual attraction can also be termed as chemical bond or binding energy.

So, depending upon the strength of mutual attraction, the nature of the element can be determined as well as its nature of reactivity can be analysed. So, results as a chemical bond from the mutual attractions of nuclei for atoms and electrons.

7 0

3 years ago

When measuring the diameter of a cylinder the following measurements are obtained.

Arlecino [84]

Answer:

a. 1.80 %

b. 0.60 %

c. 1.20 %

d. 0.60 %

e. 0.60 %

Explanation:

In order to calculate percent uncertainties in each case, we forst need to calculate the average value:

Average Diameter = (16.4 mm + 16.8 mm + 16.9 mm + 16.6 mm +16.8 mm)/5

Average Diameter = 16.7 mm

Now, the formula for percent uncertainty is:

% Uncertainty = (Uncertainty/Average) * 100 %

where,

Uncertainty = |Value - Average|

For Each Case:

a. 16.4 mm:

Uncertainty = |16.4 mm - 16.7 mm| = 0.3 mm

Therefore,

% Uncertainty = (0.3 mm/16.7 mm) * 100%

% Uncertainty = 1.80 %

b. 16.8 mm:

Uncertainty = |16.8 mm - 16.7 mm| = 0.1 mm

Therefore,

% Uncertainty = (0.1 mm/16.7 mm) * 100%

% Uncertainty = 0.60 %

c. 16.4 mm:

Uncertainty = |16.9 mm - 16.7 mm| = 0.2 mm

Therefore,

% Uncertainty = (0.2 mm/16.7 mm) * 100%

% Uncertainty = 1.20 %

d. 16.6 mm:

Uncertainty = |16.6 mm - 16.7 mm| = 0.1 mm

Therefore,

% Uncertainty = (0.1 mm/16.7 mm) * 100%

% Uncertainty = 0.60 %

e. 16.8 mm:

Uncertainty = |16.8 mm - 16.7 mm| = 0.3 mm

Therefore,

% Uncertainty = (0.1 mm/16.7 mm) * 100%

% Uncertainty = 0.60 %

7 0

3 years ago

In gym class you run 22 m horizontally, then climb a rope vertically for 6.2 m. What is the direction angle of your total displa

miskamm [114]

Im 99% sure
tan^-1 (6.2/22)= 15.7º
with 2 significant figures 16º

7 0

3 years ago

Read 2 more answers

why do a circulatory system is important in meeting the needs of all cells throughout an animals body

valentinak56 [21]

The circulatory system is important in meeting the needs of all cells in the body because it offers means of transport by which cells obtain the materials needed to live and function. The functions of the circulatory system by which the cells are supported include: 1. Respiration- oxygen is delivered to the cells and carbon dioxide is removed from them. 2. Nutrition- nutrients for energy are supplied to every cell in the body. 3. Waste removal- metabolic waste products are taken away before they accumulate and become harmful to the cells. 4. Cellular communication- hormones are transported to the cells and organs that need them for proper functioning. 5.Thermoregulation- As blood circulates, it keeps body temperature balanced and thus cells are able to carry out processes well.

3 0

3 years ago

One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a

Maurinko [17]

This question is not complete.

The complete question is as follows:

One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates “artificial gravity” at the outside rim of the station. (a) If the diameter of the space station is 800 m, how many revolutions per minute are needed for the “artificial gravity” acceleration to be 9.80m/s2?

Explanation:

a. Using the expression;

T = 2π√R/g

where R = radius of the space = diameter/2

R = 800/2 = 400m

g= acceleration due to gravity = 9.8m/s^2

1/T = number of revolutions per second

T = 2π√R/g

T = 2 x 3.14 x √400/9.8

T = 6.28 x 6.39 = 40.13

1/T = 1/40.13 = 0.025 x 60 = 1.5 revolution/minute

6 0

3 years ago