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3 years ago

How do you give an example for finding net force?

1 answer:

7 0

-- 6 people all trying to push a car out of snow

-- a Tug-o-War with 30 people of different sizes pulling on each end of the rope

-- you and your sister both pulling on the same doll (or Transformer)

-- lifting a book up from the table to a high shelf
taking a book down from a high shelf to the table
(one force is you; another force is gravity)

-- grabbing your big dog by his collar and trying to bring him inside

-- three people at the table all grab the ketchup bottle at the same time

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If two is company and three is a crowd, what is 4 and 5?

LiRa [457]

4 and 5 is 9

(4 + 5)

4 0

4 years ago

Read 2 more answers

if a piece of sea floor has moved 50 km in 5 million years what is the yearly rate of sea-floor motion?

BartSMP [9]

<span>0.0001 km / year or 10^-5 km/year just take 50 km and divide it by 5 million</span>

6 0

3 years ago

Read 2 more answers

A 1500kg car traveling at 25m/s skids to a stop. The force of friction between the tires and the road is 10500N. How far does th

ale4655 [162]

44.64m

Explanation:

Given parameters:

Mass of the car = 1500kg

Initial velocity = 25m/s

Frictional force = 10500N

Unknown:

Distance moved by the car after brake is applied = ?

Solution:

The frictional force is a force that opposes motion of a body.

To solve this problem, we need to find the acceleration of the car. After this, we apply the appropriate motion equation to solve the problem.

-Frictional force = m x a

the negative sign is because the frictional force is in the opposite direction

m is the mass of the car

a is the acceleration of the car

a = $\frac{frictional force}{mass}$ = $\frac{10500}{1500}$ = -7m/s²

Now using;

V² = U² + 2as

V is the final velocity

U is the initial velocity

a is the acceleration

s is the distance moved

0² = 25² + 2 x 7 x s

0 = 625 - 14s

-625 = -14s

s = 44.64m

learn more:

Velocity problems brainly.com/question/10932946

#learnwithBrainly

7 0

3 years ago

The shortening of a transmitted signal's wavelength and/or an increase in its frequency, which indicates that the object is

Mrrafil [7]

Answer: The Doppler effect occurs when a source of a wave is moving relative to an observer (or the observer is moving relative to the source). In this case, the apparent frequency of the sound, as heard/seen by the observer, is shifted with respect to the original frequency of the wave.

More specifically, the relationship between the apparent frequency, f', and the original frequency, f, is given by:

where:

is the velocity of the wave

is the velocity of the observer relative to the source, and it is positive if the observer is moving towards the source, and negative if the observer is moving away from the source

is the velocity of the source relative to the observer, and it is positive if the source is moving away from the observer, and negative if the source is moving towards the observer

The doppler effect occurs in many daily-life situations: for instance, when an ambulance approaches you, you hear an increase in the apparent frequency of the siren due to the Doppler effect. Another example is the movements of distant galaxies from us: when they move away from us, the apparent frequency of the light they emit decreases, so their wavelengths appear to increase towards the red color (red-shift); on the contrary, when they are moving towards us, the apparent frequency seems to increase, so the wavelength seems to decrease towards the blue color (blue-shift).

Explanation:

7 0

3 years ago

What is the Mr of HCO3

kkurt [141]

Answer:

61.0168 g/mol Explanation:

8 0

2 years ago