Rita has two small containers, one holding a liquid and one holding a gas. Rita transfers the substances to two larger container
2 answers:
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Explanation:
(a) Net force acting on the block is as follows.
or, ma = -mg Sin (\theta)[/tex]
a =
=
= -3.35
According to the kinematic equation of motion,
Distance traveled by the block before stopping is as follows.
s =
=
= 21.5 m
According to the kinematic equation of motion,
v =
0 =
= 7.16 sec
Therefore, before coming to rest the surface of the plane will slide the box till 7.16 sec.
(b) When the block is moving down the inline then net force acting on the block is as follows.
ma =
a =
=
= 3.35
Kinematics equation of the motion is as follows.
s =
21.5 m =
=
= 3.58 sec
Hence, total time taken by the block to return to its starting position is as follows.
t =
= 7.16 sec + 3.58 sec
= 10.7 sec
Thus, we can conclude that 10.7 sec time it take to return to its starting position.
Answer:
Explanation:
given,
mass of the cart 1, m₁ = 310 g
speed of car 1 , v₁ = 1.25 m/s
mass of cart 2, m₂ = 260 g
speed of cart 2, v₂ = -1.33 m/s
speed of center of mass
Hence, speed of center of mass of the system is equal to 0.0732 m/s