All categories

3 years ago

Find the domain and the range of the given relation {(-1,-5),(-3,0),(9,1),(1,9)}

Mathematics

1 answer:

Dimas [21]3 years ago

6 0

Answer:

1,3,4,6,8} { 1 , 3 , 4 , 6 , 8 }. Range:{2,4,5,7,9}

Step-by-step explanation:

The domain is the set of all the values of x x . The range is the set of all the values of y y .

You might be interested in

Write an equation of the line that passes through the given point and is parallel to the given line.

9966 [12]

Answer : <em>Equation of line is</em> y=Equation of line is y= $\frac{2}{3}$ x+ $\frac{-5}{3}$

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = $\frac{2}{3}$ x+1 is m= $\frac{2}{3}$

We know that line : y = $\frac{2}{3}$ x+1 is parallel to equation of target line.

therefore, slope of target line will be $\frac{2}{3}$ .

we write equation of target line as y= $\frac{2}{3}$ x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y= $\frac{2}{3}$ x+c

-2= $\frac{2}{3}$ $\times$ -5+ c

-5= $\frac{-10}{3}$ +c

c= $\frac{-5}{3}$

thus, Equation of line is y=Equation of line is y= $\frac{2}{3}$ x+ $\frac{-5}{3}$

7 0

3 years ago

Let T:R²->R² be a linear transformation ,and assume that T (1,2)=(-1,1) and T(1,-1)=(2,3)

zavuch27 [327]

Answer:

(-4,-1)

Step-by-step explanation:

We are given T(1,2)=(-1,1) and T(1,-1)=(2,3) and T is a linear transformation.

This implies for scalars a and b that

T(a(1,2)+b(-1,1))=aT(1,2)+bT(-1,1)

T((a,2a)+(-b,b))=a(-1,1)+b(2,3)

T((a-b,2a+b))=(-a,a)+(2b,3b)

T((a-b,2a+b))=(-a+2b,a+3b)

This means we should be able to solve the system below to find a and b for T(3,3):

a-b=3 and 2a+b=3

Add equations to eliminate b and solve for a:

3a=6

Divide 3 on both sides:

a=2

If a-b=3 and a=2, then b=-1.

Plug in a=2, b=-1:

T((a-b,2a+b))=(-a+2b,a+3b)

T((2--1,2×2+-1)=(-2+2×-1,2+3×-1)

T(3,3)=(-4,-1).

4 0

2 years ago

The perimeter of a rectangle is 36m. If its length is increased by 1m and the width is increased by 2m, its area will increase b

maw [93]

Answer:

80 m^2

Step-by-step explanation:

The given information lets you write two equations involving length (x) and width (y).

2(x +y) = 36 . . . . the perimeter is 36 m
(x+1)(y+2) -xy = 30 . . . . increasing the length and width increases area

The second of these equations simplifies to another linear equation, giving a system of linear equations easily solved.

xy +y +2x + 2 -xy = 30

2x +y = 28 . . . . . . . subtract 2

Dividing the first equation by 2 gives

x +y = 18

and subtracting this from the above equation gives ...

(2x +y) -(x +y) = 28 -18

x = 10

Then

y = 18 -10 = 8

The area of the original rectangle is xy = 10·8 = 80 m^2.

4 0

3 years ago

Are lines of symmetry also diagonals in a polygon? Explain.

Vaselesa [24]

Well not all lines are lines of symmerty, because if you draw a let's say a rectangle on a piece of paper and draw a diagonal line through it, well the two sides don't really lie perfectly on one another!!

3 0

3 years ago

Math help (radical expressions) ???

Vinil7 [7]

Answer:

radicial expressions

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers