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UNO [17]
2 years ago
9

How do small pieces of iron behave when brought close to a magnet?​

Physics
1 answer:
taurus [48]2 years ago
5 0

Answer:

When a magnet is brought near a piece of iron, the iron also gets attracted to the magnet, and it acquires the same ability to attract other pieces of iron.

Explanation:

PLEASE MARK ME AS BRAINLIST

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Both speed and velocity measure how fast something is moving. However, since speed is not a _________ it does not require a(n) _
Jet001 [13]

Both speed and velocity measure how fast something is moving. Hence, since speed is not a vector it does not require direction.

Speed only depends on the distance covered by the object and how much time it took to cover that distance. It does not care about the direction, it just depend on the length of the entire path covered. Whereas, velocity depends on magnitude as well as the direction of the object's motion for example: When an airplane is traveling, It is better to deal the motion with velocity and when we are moving in a car inside the city, we should deal the motion with speed.  

3 0
4 years ago
Are you aware of human rights violations happening in your community? Explain.​
MA_775_DIABLO [31]

Answer:

Answer: We should be aware of human rights violation happening in our community. In our community, there are so many people who cannot practice their own religion and rituals. ... In many nations around the globe, domestic violence is another disadvantage in our society and another example of "human rights violations".

Explanation:

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3 0
4 years ago
Predict the speed of a car after 10.0 s when the car’s speed follows
andreev551 [17]

Answer:

48 m/s

Explanation:

The time is 10 seconds

The speed of the car after 10 seconds when the relationship is 4.8 m/s^2 × time can be calculated as follows

= 4.8 × 10

= 48

Hence the speed is 48 m/s

7 0
4 years ago
A doubly ionized molecule (i.e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 5.
Kobotan [32]

Explanation:

The given data is as follows.

           F = 5.75 \times 10^{-16} N

          q = 1.6 \times 10^{-19} C

          v = 385 m/s

       sin (63.9^{o}) = 0.876

Now, we will calculate the magnitude of magnetic field as follows.

              B = \frac{F}{qv sin (\theta)}

                  = \frac{5.75 \times 10^{-16} N}{1.6 \times 10^{-19} C \times 385 m/s \times 0.876}

                  = 0.01065 \times 10^{3} T

                  = 10.65 T

Thus, we can conclude that magnitude of the magnetic field is 10.65 T.

4 0
3 years ago
A 2-kg cart, traveling on a horizontal air track with a speed of 3m/s, collides with a stationary 4-kg cart. The carts stick tog
ladessa [460]

Answer:

The impulse exerted by one cart on the other has a magnitude of 4 N.s.

Explanation:

Given;

mass of the first cart, m₁ = 2 kg

initial speed of the first car, u₁ = 3 m/s

mass of the second cart, m₂ = 4 kg

initial speed of the second cart, u₂ = 0

Let the final speed of both carts = v, since they stick together after collision.

Apply the principle of conservation of momentum to determine v

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 3 + 0 = v(2 + 4)

6 = 6v

v = 1 m/s

Impulse is given by;

I = ft = mΔv = m(

The impulse exerted by the first cart on the second cart is given;

I = 2 (3 -1 )

I = 4 N.s

The impulse exerted by the second cart on the first cart is given;

I = 4(0-1)

I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).

Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.

8 0
4 years ago
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