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r-ruslan [8.4K]
3 years ago
8

" When the apple falls,does the apple also attract the earth?​

Physics
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer:

yes

Explanation:

masses attract each other

with a teeny-tiny force

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Most galaxies in the Universe are moving towards the Earth. True or False.
Morgarella [4.7K]

That's false.

There are billions of galaxies in the universe. A few of the nearest ones are moving TOWARD us, and ALL the rest are moving AWAY from us.

The farther a galaxy is from us now, the faster it's moving farther away.

6 0
3 years ago
A catapult with a radial arm 3.81 m long accelerates a ball of mass 18.2 kg through a quarter circle. The ball leaves the appara
saw5 [17]

Answer:

(a)\alpha = 53.73 m/s^2

(b)   I =428 kgm^2

(c)\tau = 428 \times 53.73  = 22996 .44Nm

Explanation:

GIVEN

mass = 18.2 kg

radial arm length = 3.81 m

velocity = 49.8 m/s

mass of arm = 22.6 kg

we know using relation between linear velocity and angular velocity

\omega = \frac{v}{l}

\omega = \frac{49.8}{3.81} \\\omega = 12.99 rad/s

for  angular acceleration, use the following equation.

\omega _{f}^2 = \omega_{i}^2+2\alpha\theta

since \omega _{i} = 0

here  for one circle is 2 π radians.   therefore for one quarter of a circle is π/2 radians

so   for one quarter \theta = \frac{\pi }{2}

(12.99)^2 = 2\alpha(\frac{\pi }{2})

on solving

\alpha = \frac{168.74}{\pi }\\\alpha = 53.73 m/s^2

(b)

For the catapult,

moment of inertia

I = \frac{1}{2}MR^2

I = \frac{1}{2} \times 22.6\times 3.81 \times 3.81\I = 164kg m^2

For the ball,

I = MR^2

I = 18.2 \times 14.51

I = 264 kgm^2

so total moment of inertia =  428 kgm^2

(c)

\tau = I\alpha

\tau = 428 \times 53.73  = 22996 .44Nm

3 0
4 years ago
What is the energy (in joules) and the wavelength (in meters) of the line in the spectrum of hydrogen that represents the moveme
soldi70 [24.7K]

Answer:

The energy is 4.57x10^{-19} J and the wavelength is 4.34x10^{-7}m for the line in the spectrum of hydrogen that represents the movement of an electron from Bohr orbit with n = 2 to the orbit with n = 5.

<em>In what part of the electromagnetic spectrum do we find this radiation? </em>

In the Ultraviolet part of the electromagnetic spectrum.

Explanation:

The energy of the absorbed photon can be known by the difference in energy between the two states in which the transition is happening (In this case from n = 2 to n = 5):

E = E_{upper}-E_{lower}   (1)

The permitted energy for the atom of hydrogen, according with the Bohr's model, is defined as:

E_{n} = -\frac{13.606 eV}{n^{2}}   (2)

Or it can be expressed in Joules, since 1eV = 1.60x10^{-19}J

E_{n} = -\frac{2.18x10^{-18} J}{n^{2}}   (3)

Where the value -2.18x10^{-18} represents the energy of the ground state¹ and n is the principal quantum number.

For the case of n = 2:

E_{2} = -\frac{2.18x10^{-18} J}{(2)^{2}}

E_{2} = -5.45x10^{-19} J

For the case of n = 5:

E_{5} = -\frac{2.18x10^{-18} J}{(5)^{2}}

E_{5} = -8.72x10^{-20} J

Replacing those values in equation (1) it is gotten:

E = -8.72x10^{-20} J-(-5.45x10^{-19} J )

E = 4.57x10^{-19} J

The wavelength can be determined by means of the Rydberg formula:

\frac{1}{\lambda} = R(\frac{1}{n_{l}^{2}}-\frac{1}{n_{u}^{2}})  (4)

Where R is the Rydberg constant, with a value of 1.097x10^{7}m^{-1}

For this particular case n_{l} = 2 and n_{u} = 5:

\frac{1}{\lambda} = 1.097x10^{7}m^{-1}(\frac{1}{(2)^{2}}-\frac{1}{(5)^{2}})

\frac{1}{\lambda} = 1.097x10^{7}m^{-1}(0.21)

\frac{1}{\lambda} = 2303700m^{-1}

\lambda = \frac{1}{2303700m^{-1}}

\lambda = 4.34x10^{-7}m

So the energy is 4.57x10^{-19} J and the wavelength is 4.34x10^{-7}m for the line in the spectrum of hydrogen that represents the movement of an electron from Bohr orbit with n = 2 to the orbit with n = 5.

<em>In what part of the electromagnetic spectrum do we find this radiation? </em>

In the Ultraviolet part of the electromagnetic spectrum.

Key terms:

¹Ground state: State of minimum energy.  

8 0
3 years ago
A box with a weight of 100 N rests on a horizontal floor. The coefficient of static friction is = 0,40 and the coefficient of ki
kompoz [17]
Weight=100N
SF=0.4
KF=0.3
Magnitude?
0.4 x 0.3 = 0.12
0.12x100=12
Ans =20
7 0
3 years ago
Can someone help me with one question? <br><br> “Do cells in the body help you grow?”
noname [10]

Body tissues grow by increasing the number of cells that make them up. Cells in many tissues in the body divide and grow very quickly between conception and adulthood.
5 0
3 years ago
Read 2 more answers
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