Bar Graphs and line Graphs (PLEASE HELP)

Mathematics

2 answers:

Alexeev081 [22]2 years ago

7 0

take the bar graph and then make the bar graph more evaluated then

The End

lbvjy [14]2 years ago

4 0

1. 20 // 2. Jan // 3. 10 // 4. oct and nov // 5. bar graph. // 6. Line graph.

You might be interested in

What is the value of x in the equation 2(x−3) 9=3(x 1) x? x = −3 x = −1 x = 0 x = 3

Masja [62]

The solution of the linear equation is x = 0.

<h3>What is the linear equation?</h3>

An equation is a mathematical statement, which has an equal sign (=) between the algebraic expression.

Linear equations are the equations of degree 1.

The given linear equation is;

$\rm 2(x-3)+ 9=3(x+ 1) +x$

The value of x is determined in the following steps given below. $\rm 2(x-3)+9=3(x+1)+x\\\\2x-6+9=3x+3+x\\\\\ 2x+3=4x+3\\\\3-3=4x-2x\\\\0=2x\\\\x=0$

Hence, the solution of the linear equation is x = 0.

To know more about linear equations click the link given below.

brainly.com/question/5085290

8 0

1 year ago

NO LINKS!!!! Find the equation of the circle below

inysia [295]

Answer:

$(x+3)^2+(y-2)^2=9$

Step-by-step explanation:

<u>Equation of a circle</u>

$(x-a)^2+(y-b)^2=r^2$

where:

(a, b) is the center
r is the radius

From inspection of the diagram, the center of the circle <em>appears</em> to be at point (-3, 2), although this is not very clear. Therefore, a = -3 and b = 2.

Substitute these values into the general form of the equation of a circle:

$\implies (x-(-3))^2+(y-2)^2=r^2$

$\implies (x+3)^2+(y-2)^2=r^2$

Again, from inspection of the diagram, the <u>maximum vertical point</u> of the circle appears to be at y = 5. Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

⇒ radius (r) = 5 - 2 = 3

Substitute the found value of r into the equation:

$\implies (x+3)^2+(y-2)^2=3^2$