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2 years ago

Bar Graphs and line Graphs (PLEASE HELP)

Mathematics

2 answers:

Alexeev081 [22]2 years ago

7 0

take the bar graph and then make the bar graph more evaluated then

The End

lbvjy [14]2 years ago

4 0

1. 20 // 2. Jan // 3. 10 // 4. oct and nov // 5. bar graph. // 6. Line graph.

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Line Equation from Two Points

Verdich [7]

Hi!

We can use point-slope form to solve this.

$y-y_{1} =m(x -x_{1})$

$y_{1}$ and $x_{1}$ will be from one of the points.

First, we have to find $m$ , the slope. We can use the slope equation to get this.

$\frac{y_{1} -y_{2} }{x_{1} -x_{2} }$

Plug in your points:

$\frac{4-0}{8-(-8)} =\frac{4-0}{8+8} =\frac{4}{16} =\frac{1}{4}$

Your slope is $\frac{1}{4}$

Now plug points and slope into point-slope equation. We will use (8, 4).

$y-4=\frac{1}{4} (x-8)$

Now, if you want to get it into y = mx + b form, you have to solve for y:

$y-4=\frac{1}{4} (x-8)$

$y-4=\frac{1}{4} x-2$

$y=\frac{1}{4} +2$

Your equation is $y=\frac{1}{4} +2$

For more information on how to get the equation of a line when given two points, see here:

brainly.com/question/986503

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2 years ago

Whats 9387c x 732l +99 *DO NOT REPORT TY!*

IRISSAK [1]

Answer:

You did not even start the meeting them you want us to join . Silly

Step-by-step explanation:

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Write the equation of a line perpendicular to 5x - 7y =-6 that passes through the point (-5,6)

Likurg_2 [28]

9514 1404 393

Answer:

7x +5y = -5

Step-by-step explanation:

You can find the perpendicular line by swapping the x- and y-coefficients, and negating one of them. The new constant can be found by using the given point.

7x +5y = 7(-5) +5(6) = -5

The perpendicular line through (-5, 6) is ...

7x +5y = -5

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3 years ago

Ashley use 3 yards of ribbon to wrap these presents how many feet and rub it did actually how many inches did she

Alchen [17]

Answer:

108 inches

Step-by-step explanation:

one yard = 36 inches

multiply 36 by 3

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If 10 is added to each observation and the following data set what is the relationship between the original standard deviation a

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