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2 years ago

In order to solve x 2 + 12 x = 2 by completing the square, what value must be added to both sides?

Mathematics

1 answer:

Arada [10]2 years ago

7 0

Answer:

Step-by-step explanation:

x^2 + 12 x = 2

In order to complete the square we need to add ( b/2)^2 to each side where b is the coefficient of the x term

b=12

12/2 = 6

6^2 = 36

We need to add 36 to each side

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3 years ago

Please help, and thank you!

lawyer [7]

Answer:

3. C

4. D

Step-by-step explanation:

$x^2+25=0\\x^2=-25\\x=\pm\sqrt{-25}$

Once $\sqrt{-1}=i$

$x=\pm5i$

A quadratic equation has no real roots when the discriminant ( $\Delta$ ) is negative. $\Delta$ .

Let's try all the equations:

(A)

$2x^2-7x-9=0\\\\\Delta=\sqrt{\left(-7\right)^2-4\cdot \:2\left(-9\right)}\\\Delta=\sqrt{\left(-7\right)^2+4\cdot \:2\cdot \:9}\\\Delta=\sqrt{121} \\\Delta=11$

(B)

$2x^2=7x\\2x^2-7x=0\\x(2x-7)=0\\x=0\\\text{or}\\2x-7=0\\2x=7\\\\$

$x=\frac{7}{2}$

(C)

$2x^2+7x-9=0\\\Delta = \sqrt{7^2-4\cdot \:2\left(-9\right)}\\\Delta = \sqrt{7^2+4\cdot \:2\cdot \:9}\\\Delta = \sqrt{121} \\\Delta= 11$

(D)

$2x^2-7x+9=0\\\Delta = \sqrt{\left(-7\right)^2-4\cdot \:2\cdot \:9}\\\\\Delta=\sqrt{-23} \\\Delta=\sqrt{23i}$

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2 years ago

40% of what number is 80

Arte-miy333 [17]

40%*2=80 I hope I helped!

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2 years ago