The slope would be 8.92g/cm^3.
<em>D = m/V</em>
<em>m = DV
</em>
The equation for a straight line is
<em>y</em> = m<em>x</em> +b, where m is the slope and b is the y-intercept. We have
<em>m</em> = D<em>V</em> + 0
Thus, a plot of <em>m</em> vs <em>V</em> will give a straight line with a slope of <em>D</em> and a
<em>y</em>-intercept at the origin.
Slope = <em>D</em> = 8.92g/cm^3
0.1/200= 0.0005 , u need to dissolve .0005 grams of sugar
Answer:
392
Explanation:
According to the law of conservation of energy, energy cannot vanish,so the lost potential energy must be converted into another form of energy (in this case, Kinetic Energy).
(mass*g*height)-(mass*g*halfway height)=(2*9.8*40)-(2*9.8*20)
784-392=392
This makes sense because since the rock has fallen halfway, half of its potential energy has become kinetic energy. Once the rock reaches a height of 0 Meter, all of its potential energy will be kinetic energy.
<span>Ionic bonding is the entire exchange of valence electron(s) between particles. It is a kind of substance security that creates two oppositely charged particles. In ionic bonds, the metal loses electrons to wind up plainly an emphatically charged cation, though the nonmetal acknowledges those electrons to end up noticeably a contrarily charged anion.</span>
Answer:
The theoretical yield of urea = <u>120.35kg</u>
The percent yield for the reaction = <u>72.70%</u>
Explanation:
Lets calculate -
The given reaction is -
→
Molar mass of urea 
= 60g/mole
Moles of 
= 
(since 
)
= 4011.76 moles
Moles of 
= 
= 
= 2386.36 moles
Theoritically , moles of required = double the moles of
but , 
, the limiting reagent is
Theoritical moles of urea obtained = 
= 
Mass of 2005.88 mole of =
= 120352.8g
= 120.35kg
Therefore , theroritical yeild of urea = 120.35kg
Now , Percent yeild = 
72.70%
Thus , the percent yeild for the reaction is 72.70%
