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3 years ago

Równania reakcji chemicznej

Chemistry

1 answer:

Aliun [14]3 years ago

5 0

Answer:

Reakcja chemiczna jest opisana równaniem chemicznym, wyrażeniem określającym tożsamość i ilość substancji biorących udział w reakcji. Równanie chemiczne pokazuje początkowy związek (związki) - reagenty - po lewej stronie, a końcowy związek (związki) - produkty - po prawej stronie, oddzielone strzałką.

Explanation:

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3 years ago

Read 2 more answers

I know there are 4.5*10^-9 seconds in 4.5 nanoseconds, but when I enter it into my TI-30xIIs, I get 4.5*10^-10. I enter it as 4.

o-na [289]

Answer:

You are not using properly the function exponential in your calculator

Explanation:

When a number is too big or too small we use scientific notation. This is a number between 1 a 10 multiplied by a power of 10.

When you are writing 4.5*10^-9 you are actually writing 0.0000000045 in scientific notation.

When you enter this in the calculator you have to use the function EXP after the first two numbers.

Steps: 1) Enter 4.5

2) Enter EXP

3) Enter minus (-)

4) Enter 9

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3 years ago

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2 years ago

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Dmitriy789 [7]

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2 years ago

Since helium is lighter than air, it is difficult to measure the mass of a sample, so to find out the mass of helium in a birthd

d1i1m1o1n [39]

Answer:

0.7457 g is the mass of the helium gas.

Explanation:

Given:

Pressure = 3.04 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25.0 + 273.15) K = 298.15 K

Volume = 1.50 L

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K

<u>⇒n = 0.1863 moles</u>

Molar mass of helium = 4.0026 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.1863\ mole= \frac{Mass}{4.0026\ g/mol}$

$Mass_{He}= 0.7457\ g$

<u>0.7457 g is the mass of the helium gas. </u>

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2 years ago