Answer:
An alkali metal present in period 2 have larger first ionization energy.
Explanation:
Ionization energy:
The amount of energy required to remove the electron from the atom is called ionization energy.
Trend along period:
As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.
Trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus. Thus alkali metal present in period 2 have larger ionization energy because of more nuclear attraction as compared to the alkali metal present in period 4.
Answer:
New volume is 14.35 mL
Explanation:
When a system of a gas keeps on constant its temperature and number of moles, the pressure is modified indirectly proportional to the volume:
Pressure increased → Volume decreased
Pressure decreased → Volume increased.
The relation you have to apply is: P₁ . V₁ = P₂. V₂
1.23 atm . 35 mL = 3 atm . V₂
(1.23 atm . 35 mL / 3 atm) = V₂
V₂ = 14.35 mL
Oxidation is a process when an atom, a group of atoms, or an ion loses electrons.
For example,
Cu⁰ -------> Cu⁺² + 2e⁻. This is an oxidation process.
As we can see an oxidation number was 0, and it became +2. The oxidation number is increased. Oxidation number of the atom, when an atom has undergone oxidation, increases.
So, answer is b.False.
The answer is c.) Rutherford model
Answer:A
Explanation:For a given amount of solute, smaller particles have greater surface area. With greater surface area, there can be more contact between particles of solute and solvent.
