Answer:
The answer is option B, x = 4.2
Answer: area of the outer part of the rug= 16 -x²
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
Area of a square: Side²
Since the area of the rug including the inner square is:
Area of the rug = 4² =16 in²
And the area of the inner square is equal to:
Area if the inner square = x²
To obtain the area of the outer part of the rug we have to subtract the area of the inner square to the area of the rug.
Area of the outer part of the rug= 16 -x²
Feel free to ask for more if needed or if you did not understand something.
Answer:
xlog(64)−xlog(2)−2
Step-by-step explanation:
Simplify 6log(2) by moving 6 inside the logarithm.
log(2^6)x − log(2)x − 2
Raise 2 to the power of 6.
log(64)x − log(2)x − 2
Reorder factors in log(64)x − log(2)x −2.
The height of the tank must be at least 1 foot, or 12 inches. We know the floor area (which is length x width) must be at least 400 inches. Therefore these minimum dimensions already tell us that the minimum volume is 400 x 12 = 4800 cubic inches. Since we have a maximum of 5000 cubic inches, the volume must be within the range of 4800 - 5000 cubic inches.
We can set the height at exactly 1 ft (or 12 inches). Then we can select length and width that multiply to 400 square inches, for example, L = 40 inches and W = 10 in. This gives us a tank of dimensions 40 x 10 x 12 = 4800 cubic inches, which fits all the criteria.
d
Step-by-step explanation:
