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Dominik [7]
3 years ago
11

4x + 2y = -12 3x + y = -10 please help system by substitution.

Mathematics
1 answer:
padilas [110]3 years ago
3 0

Answer:

(-4, 2)

Step-by-step explanation:

4x+2y=-12

3x+y=-10

Start by dividing the first equation by 2 to simplify it...

2x+y=-6

Then, subtract -2x from both sides to isolate y...

y=-2x-6

Substitute -2x-6 for y in the second equation...

3x-2x-6=-10

Combine like terms...

x-6=-10

Add 6 to both sides

x-6+6=-10+6

x=-4

Plug -4 in for x to solve for y:

3(-4)+y=-10

-12+y=-10

Add 12 to both sides

-12+12+y=-10+12

y=2

(x,y)=(-4,2)

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Which of the following statements correctly uses the distributive property?
Anna007 [38]

Answer:

d)  9(-7+6) = 9(-7) + 9(6)  is the correct use of Distributive Property.

Step-by-step explanation:

Distributive Property states that form any three expressions A, B and C

1.   A( B -C)  = AB - AC

2.  A (B + C ) = AB + AC

Now, here

a)  0-3(12+5)= -3(12) - (-3)(5)

Solving Left side by distributive property, we get

0-3(12+5)  = -3(12) + (-3)(5)  

and -3(12) + (-3)(5)   ≠  Right Side      -3(12) - (-3)(5)

⇒NO CORRECT USE OF DISTRIBUTIVE PROPERTY

b)  7(19 - 8) = 7(19) - 8

Solving Left side by distributive property, we get

7(19 - 8) = 7(19) - 7(8)  

and 7(19) - 7(8)    ≠  Right Side      7(19) - 8

⇒NO CORRECT USE OF DISTRIBUTIVE PROPERTY

c)  -2(15 - 3) = -2(15) + (-2)(3)

Solving Left side by distributive property, we get

-2(15 - 3) =   -2(15) - (-2)(3)

and -2(15) - (-2)(3)   ≠  Right Side     -2(15) + (-2)(3)

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d)  9(-7+6) = 9(-7) + 9(6)

Solving Left side by distributive property, we get

9(-7+6) =   9(-7) +  9(6)

and  9(-7) +  9(6)  = Right Side 9(-7) + 9(6)

⇒ CORRECT USE OF DISTRIBUTIVE PROPERTY

3 0
3 years ago
Apel Sinoman has 100 ft of fencing material to enclose a rectangular exercise run for her dog. One side of the run will border h
Olegator [25]

Answer:

For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.

Step-by-step explanation:

Let the length of the rectangular exercise run = l ft

and width of the run = w ft

Sinoman has to cover a rectangular exercise run from three sides with the fencing material,

So length of the material = (l + 2w) ft

l + 2w = 100

l = 100 - 2w --------(1)

Area of the rectangular area covered = Length × width

A = lw

A = w(100 - 2w)    [(l = 100 - 2w)from equation (1)

For maximum area we find the derivative of area and equate it to zero.

\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]

A'=\frac{d}{dw}(100w-2w^{2} )

A' = 100 - 4w

For A' = 0

100 - 4w = 0

4w = 100

w = 25 ft

From equation (1)

l = 100 - 2w

l = 100 - 2×(25)

l = 50 ft

Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.

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